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Please help:)
Show the state of the stack and the value of each variable after execution of each of the following statements:
p=2.5 q=3.30 r=7.003 d=0.00026
create stack
push q onto stack
push d onto stack
pop item from stack
push r onto stack
push p onto stack
p=q*r
push p+r+d onto stack
pop item from stack and store in p
pop item from stack and store in q
pop item from stack and store in r
 one year ago
 one year ago
Please help:) Show the state of the stack and the value of each variable after execution of each of the following statements: p=2.5 q=3.30 r=7.003 d=0.00026 create stack push q onto stack push d onto stack pop item from stack push r onto stack push p onto stack p=q*r push p+r+d onto stack pop item from stack and store in p pop item from stack and store in q pop item from stack and store in r
 one year ago
 one year ago

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tyteen4a03Best ResponseYou've already chosen the best response.0
Create Stack: *bzzt* Push q onto stack, stack becomes [q] Push d onto stack, stack becomes [q, d] pop item from stack, stack becomes [d] push r onto stack, stack becomes [d, r] push p onto stack, stack becomes [d. r. p] p=q*r, stack becomes [d, r, q*r] push p+r+d onto stack, stack becomes [d, r, q*r, p+r+d] pop item from stack and store in p, p becomes d pop item from stack and store in q. q becomes r pop item from stack and store in r, r becomes q*r.
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.1
create stack push q onto stack[q] push d onto stack[q,d] pop item from stack[q] push r onto stack[q,r] push p onto stack[q,r,p] p=q*r // do nothing push p+r+d onto stack[q, r, p, (p[q * r]+r+d)] pop item from stack and store in p [q,r,p] // (p[q * r]+r+d)] = p pop item from stack and store in q [q,r] // p = q pop item from stack and store in r [q] // r = r
 one year ago

ajprincessBest ResponseYou've already chosen the best response.0
@KonradZuse Can u please explain me the line push p+r+d onto stack[q, r, p, (p[q * r]+r+d)] Why it is p[q*r]? I dnt get that part.
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.1
I meant p = q * r, syntax fail on my part.
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.1
p + r + d or (r*d) + d + r
 one year ago

ajprincessBest ResponseYou've already chosen the best response.0
u mean p+r+d=(q*r)+d+r?
 one year ago

ajprincessBest ResponseYou've already chosen the best response.0
@KonradZuse so it will be create stack push q onto stack[q] push d onto stack[q,d] pop item from stack[q] push r onto stack[q,r] push p onto stack[q,r,p] p=q*r // do nothing push p+r+d onto stack[q, r, p, ([q * r]+r+d)] pop item from stack and store in p [q,r,p] // ([q * r]+r+d)] = p pop item from stack and store in q [q,r] // p = q pop item from stack and store in r [q] // r = r. Isn't t?
 one year ago

tyteen4a03Best ResponseYou've already chosen the best response.0
@KonradZuse D'oh, messed up stacks with queues.
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.1
yes remember queues are first in first out(think of a line of school children, or lunch line) then stacks are first in last out, so think of a stack of papers. If you put a papper at the bottom, you need to do all the papers on top of it first to get to that one paper.
 one year ago

KonradZuseBest ResponseYou've already chosen the best response.1
not too sure why r = r, but that's how it's supposed to be done.....
 one year ago

ajprincessBest ResponseYou've already chosen the best response.0
oh k. thank u soooo much @KonradZuse
 one year ago
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