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anonymous
 4 years ago
Application of differentiation.
Find the equation of the normal to the curve y=(x+2)e^x3x at the point (0,2).
anonymous
 4 years ago
Application of differentiation. Find the equation of the normal to the curve y=(x+2)e^x3x at the point (0,2).

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dy/dx at (0,2) = 0 i don't know what to do next.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@ startanewww what did you get on your derivative at (0,2)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0after getting the slope at (0,2) find the normal means perpendicular to the line at (0,2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01st find the equation of tangent to the curve...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0slope perpendicular to it is m2=  1/m1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but the slope I found for dy/dx at (0,2) is zero. What can i do?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then, the slope of the normal will be 1/0 = infinity how can i find the equation of normal?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Diffrentiate y=(x+2)e^x3x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u know Product Rule ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SO...Slope of Normal = 1 / m1 = 1/1 = 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nw just write the equation using points (0,2) m = 1 yy1 = m(xx1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y'=e^x+(x+2)e^x3 dy/dx at (0,2) = e^0 + (0+2)e^0  3 = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y=(x+2)e^x3x y' = (x+2) *1 + e^x *1  3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0differentiating e^x gives e^x right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lets say y'=0, can you form a line perpendicular to the curve? try it :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first fint an equation of the line tangent to the curve at (0,2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what about the equation of normal?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes correct :D then ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the slope will be infinity....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what is a line perpendicular to line y=2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0will the slope of the normal be infinity ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1356675309579:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i don't know the answer....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think you are right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah ok theres no answer in the book? :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my classmates said the answer was x=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm the line perpendicular to y=2 is the y axis or the vertical line

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so the answer should be x=0 only?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it could be y= 0 to 2, or 2 to infinity, or y= 0 to negative infinity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0equation of the normal at (0,2)...? should there be only one answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because line tangent to the curve is y=2 or the horizontal line, now the line normal to it is the line perpendicular to y=2,, w/c are ________ ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the vertical line y axis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what is the final answer? x=0 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i would say at point (0,2) it is y= from 0 to 2 vertical line

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok YW,,, good luck now :D
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