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Application of differentiation.
Find the equation of the normal to the curve y=(x+2)e^x3x at the point (0,2).
 one year ago
 one year ago
Application of differentiation. Find the equation of the normal to the curve y=(x+2)e^x3x at the point (0,2).
 one year ago
 one year ago

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startanewwwBest ResponseYou've already chosen the best response.0
dy/dx at (0,2) = 0 i don't know what to do next.
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
@ startanewww what did you get on your derivative at (0,2)?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
after getting the slope at (0,2) find the normal means perpendicular to the line at (0,2)
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.1
1st find the equation of tangent to the curve...
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
slope perpendicular to it is m2=  1/m1
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
but the slope I found for dy/dx at (0,2) is zero. What can i do?
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
then, the slope of the normal will be 1/0 = infinity how can i find the equation of normal?
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.1
Diffrentiate y=(x+2)e^x3x
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.1
SO...Slope of Normal = 1 / m1 = 1/1 = 1
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.1
Nw just write the equation using points (0,2) m = 1 yy1 = m(xx1)
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
y'=e^x+(x+2)e^x3 dy/dx at (0,2) = e^0 + (0+2)e^0  3 = 0
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.1
y=(x+2)e^x3x y' = (x+2) *1 + e^x *1  3
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
differentiating e^x gives e^x right?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
lets say y'=0, can you form a line perpendicular to the curve? try it :D
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
first fint an equation of the line tangent to the curve at (0,2)
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
(y2)/(x0)=0 y=2?
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
what about the equation of normal?
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
the slope will be infinity....
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
what is a line perpendicular to line y=2?
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
will the slope of the normal be infinity ?
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
but 1/0 = infinity?
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
i don't know the answer....
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
i think you are right
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
ah ok theres no answer in the book? :D
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
my classmates said the answer was x=0
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
hmm the line perpendicular to y=2 is the y axis or the vertical line
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
ok so the answer should be x=0 only?
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
x = 0 to infinity?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
it could be y= 0 to 2, or 2 to infinity, or y= 0 to negative infinity
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
equation of the normal at (0,2)...? should there be only one answer?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
because line tangent to the curve is y=2 or the horizontal line, now the line normal to it is the line perpendicular to y=2,, w/c are ________ ?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
the vertical line y axis
 one year ago

startanewwwBest ResponseYou've already chosen the best response.0
so what is the final answer? x=0 ?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
i would say at point (0,2) it is y= from 0 to 2 vertical line
 one year ago

mark_o.Best ResponseYou've already chosen the best response.2
ok YW,,, good luck now :D
 one year ago
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