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tp1

  • 3 years ago

The sum of 40 consecutive intergers is 100. What is the largest of these integers?

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  1. muhammad9t5
    • 3 years ago
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    hi let it an integer is x

  2. muhammad9t5
    • 3 years ago
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    then x+x+1+x+2.........................x+40=100

  3. hartnn
    • 3 years ago
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    if the 1st integer is x then 40th integer = x+39 so, x+x+1+.....x+39 = 100

  4. hartnn
    • 3 years ago
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    now, notice that there will be 40 'x's, and the constants are 1+2+3+...38+39 to find, 1+2+3+...38+39 use, the formula for sum of first terms = \(n(n+1)/2\) here n=39. so, it'll be 40x+ 39*40/2 =100 or 40x + 20*39 = 100 now can u find 'x' from this equation ??

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