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tp1
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The sum of 40 consecutive intergers is 100. What is the largest of these integers?
 one year ago
 one year ago
tp1 Group Title
The sum of 40 consecutive intergers is 100. What is the largest of these integers?
 one year ago
 one year ago

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muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.0
hi let it an integer is x
 one year ago

muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.0
then x+x+1+x+2.........................x+40=100
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
if the 1st integer is x then 40th integer = x+39 so, x+x+1+.....x+39 = 100
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
now, notice that there will be 40 'x's, and the constants are 1+2+3+...38+39 to find, 1+2+3+...38+39 use, the formula for sum of first terms = \(n(n+1)/2\) here n=39. so, it'll be 40x+ 39*40/2 =100 or 40x + 20*39 = 100 now can u find 'x' from this equation ??
 one year ago
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