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ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{0}^{5}f(x)dx=8\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{0}^{5}g(x)=4\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
find\[\int\limits_{5}^{5}[f(x)+g(x)]dx\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{5}^{0}[f(x)+g(x)] +\int\limits_{0}^{5}[f(x)+g(x)] dx\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
after that i have no idea
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i know the 2nd part 12
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
well even mean f(x)=f(x) will that mean\[\int\limits_{5}^{0}f(x)=8\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
because\[\int\limits_{5}^{0}f(x)=8 \]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
even aplies if negative in f(x)? f(x)=f(x)
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
Why should \[\int\limits_{5}^{0}f(x)=8\]be true? I think this should be 8 and not 8.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
because that is the rule right to flip flop  should be their
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
\[\int_0^5 f(x)=8\]\[\int_5^0 f(x)=8\]\[\int_5^0 f(x)=8\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{5}^{0}f(x)=\]
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
But you're certainly on the right path to solving this. You know\[\int\limits_{0}^{5}[f(x)+g(x)] dx=12\]So you just need to find \[\int\limits_{5}^{0}[f(x)+g(x)]dx =\int\limits_{5}^0f(x)\;dx+\int\limits_{5}^0g(x)\;dx\]First, lets start with the f(x) part.
 one year ago

zepp Group TitleBest ResponseYou've already chosen the best response.0
I drove by to say hello to @KingGeorge!
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
Since \(f(x)=f(x)\), we have that \[\begin{aligned} \int\limits_{5}^0f(x)\;dx&=\int\limits_{5}^0f(x)\;dx \\ &=\int\limits_{5}^0f(x)\;dx\\ &=\int\limits_{5}^0f(u)\;(du)\qquad\text{this is a usub for }u=x.\\ &=\int\limits_0^5f(u)\;du\\ &=\int\limits_0^5f(u)\;du\\ &=8 \end{aligned}\]
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
This is basically the same thing you do for \(g(x)\). Instead we have \(g(x)=g(x)\).If we repeat the above argument, we get to the point \[\int\limits_0^5g(u)\;du\]Substitute for \(g(u)\), and we get \[\int\limits_0^5g(u)\;du=4\]
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
Did this all make sense? And hello to you too @zepp!
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i i got it i did little bit different i took u=x and then du=dx
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
There is a typo in my work two posts above. The second line should not be there. (The line that reads \(=\int_{5}^0f(x)\;dx\)).
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
That works as well.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1356649511965:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
ohk thx a lot
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
You're welcome.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i will work on this if i have nay questions can i post on this wall
 one year ago
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