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ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{0}^{5}f(x)dx=8\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{0}^{5}g(x)=4\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1find\[\int\limits_{5}^{5}[f(x)+g(x)]dx\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{5}^{0}[f(x)+g(x)] +\int\limits_{0}^{5}[f(x)+g(x)] dx\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1after that i have no idea

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1i know the 2nd part 12

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1well even mean f(x)=f(x) will that mean\[\int\limits_{5}^{0}f(x)=8\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1because\[\int\limits_{5}^{0}f(x)=8 \]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1even aplies if negative in f(x)? f(x)=f(x)

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.3Why should \[\int\limits_{5}^{0}f(x)=8\]be true? I think this should be 8 and not 8.

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1because that is the rule right to flip flop  should be their

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.3\[\int_0^5 f(x)=8\]\[\int_5^0 f(x)=8\]\[\int_5^0 f(x)=8\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{5}^{0}f(x)=\]

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.3But you're certainly on the right path to solving this. You know\[\int\limits_{0}^{5}[f(x)+g(x)] dx=12\]So you just need to find \[\int\limits_{5}^{0}[f(x)+g(x)]dx =\int\limits_{5}^0f(x)\;dx+\int\limits_{5}^0g(x)\;dx\]First, lets start with the f(x) part.

zepp
 2 years ago
Best ResponseYou've already chosen the best response.0I drove by to say hello to @KingGeorge!

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.3Since \(f(x)=f(x)\), we have that \[\begin{aligned} \int\limits_{5}^0f(x)\;dx&=\int\limits_{5}^0f(x)\;dx \\ &=\int\limits_{5}^0f(x)\;dx\\ &=\int\limits_{5}^0f(u)\;(du)\qquad\text{this is a usub for }u=x.\\ &=\int\limits_0^5f(u)\;du\\ &=\int\limits_0^5f(u)\;du\\ &=8 \end{aligned}\]

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.3This is basically the same thing you do for \(g(x)\). Instead we have \(g(x)=g(x)\).If we repeat the above argument, we get to the point \[\int\limits_0^5g(u)\;du\]Substitute for \(g(u)\), and we get \[\int\limits_0^5g(u)\;du=4\]

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.3Did this all make sense? And hello to you too @zepp!

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1i i got it i did little bit different i took u=x and then du=dx

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.3There is a typo in my work two posts above. The second line should not be there. (The line that reads \(=\int_{5}^0f(x)\;dx\)).

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1356649511965:dw

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1i will work on this if i have nay questions can i post on this wall
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