Spartan_Of_Ares
@mathstudent55



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mathstudent55
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Remember what we did before. Factor the 18 in the radical in the numerator.

mathstudent55
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Then look at the denominator, what is sqrt(36)?

Spartan_Of_Ares
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divide by 6 and 6

mathstudent55
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18 is in a radical. What are the the prime factors of 18?
Yes, sqrt(36) = 6

Spartan_Of_Ares
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3 3 2

mathstudent55
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You have two factors that are the same. That means you can pull them out of the radical.

mathstudent55
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dw:1356660281296:dw

mathstudent55
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As you know, sqrt(36) = 6. That's in the denomniator. Also as you wrote, 18 = 3 x 3 x 2. That's in the radical in the numerator.

mathstudent55
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dw:1356660403586:dw

Spartan_Of_Ares
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wait wouldnt 3 be outside the radical?

Spartan_Of_Ares
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nevermind TT

mathstudent55
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Right. I didn't take it out yet, but that's correct. sqrt(9) = 3

mathstudent55
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dw:1356660480815:dw

Spartan_Of_Ares
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thats not complete right?

mathstudent55
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Now the last step is to divide the 3 in the numerator and the 18 in the denominator by the largest number that divides into both.

Spartan_Of_Ares
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so 3 to get 2/6

mathstudent55
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3/3 = 1
18/3 = 6

mathstudent55
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dw:1356660621873:dw

mathstudent55
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Not 2/6, but sqrt(2)/6

Spartan_Of_Ares
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thanks for the help!

mathstudent55
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wlcm