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Spartan_Of_Ares

  • one year ago

@mathstudent55

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  1. Spartan_Of_Ares
    • one year ago
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  2. mathstudent55
    • one year ago
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    Remember what we did before. Factor the 18 in the radical in the numerator.

  3. mathstudent55
    • one year ago
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    Then look at the denominator, what is sqrt(36)?

  4. Spartan_Of_Ares
    • one year ago
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    divide by 6 and 6

  5. mathstudent55
    • one year ago
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    18 is in a radical. What are the the prime factors of 18? Yes, sqrt(36) = 6

  6. Spartan_Of_Ares
    • one year ago
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    3 3 2

  7. mathstudent55
    • one year ago
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    You have two factors that are the same. That means you can pull them out of the radical.

  8. mathstudent55
    • one year ago
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    |dw:1356660281296:dw|

  9. mathstudent55
    • one year ago
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    As you know, sqrt(36) = 6. That's in the denomniator. Also as you wrote, 18 = 3 x 3 x 2. That's in the radical in the numerator.

  10. mathstudent55
    • one year ago
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    |dw:1356660403586:dw|

  11. Spartan_Of_Ares
    • one year ago
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    wait wouldnt 3 be outside the radical?

  12. Spartan_Of_Ares
    • one year ago
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    nevermind T-T

  13. mathstudent55
    • one year ago
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    Right. I didn't take it out yet, but that's correct. sqrt(9) = 3

  14. mathstudent55
    • one year ago
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    |dw:1356660480815:dw|

  15. Spartan_Of_Ares
    • one year ago
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    thats not complete right?

  16. mathstudent55
    • one year ago
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    Now the last step is to divide the 3 in the numerator and the 18 in the denominator by the largest number that divides into both.

  17. Spartan_Of_Ares
    • one year ago
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    so 3 to get 2/6

  18. mathstudent55
    • one year ago
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    3/3 = 1 18/3 = 6

  19. mathstudent55
    • one year ago
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    |dw:1356660621873:dw|

  20. mathstudent55
    • one year ago
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    Not 2/6, but sqrt(2)/6

  21. Spartan_Of_Ares
    • one year ago
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    thanks for the help!

  22. mathstudent55
    • one year ago
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    wlcm

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spraguer (Moderator)
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