anonymous
  • anonymous
@mathstudent55
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1 Attachment
mathstudent55
  • mathstudent55
Remember what we did before. Factor the 18 in the radical in the numerator.
mathstudent55
  • mathstudent55
Then look at the denominator, what is sqrt(36)?

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More answers

anonymous
  • anonymous
divide by 6 and 6
mathstudent55
  • mathstudent55
18 is in a radical. What are the the prime factors of 18? Yes, sqrt(36) = 6
anonymous
  • anonymous
3 3 2
mathstudent55
  • mathstudent55
You have two factors that are the same. That means you can pull them out of the radical.
mathstudent55
  • mathstudent55
|dw:1356660281296:dw|
mathstudent55
  • mathstudent55
As you know, sqrt(36) = 6. That's in the denomniator. Also as you wrote, 18 = 3 x 3 x 2. That's in the radical in the numerator.
mathstudent55
  • mathstudent55
|dw:1356660403586:dw|
anonymous
  • anonymous
wait wouldnt 3 be outside the radical?
anonymous
  • anonymous
nevermind T-T
mathstudent55
  • mathstudent55
Right. I didn't take it out yet, but that's correct. sqrt(9) = 3
mathstudent55
  • mathstudent55
|dw:1356660480815:dw|
anonymous
  • anonymous
thats not complete right?
mathstudent55
  • mathstudent55
Now the last step is to divide the 3 in the numerator and the 18 in the denominator by the largest number that divides into both.
anonymous
  • anonymous
so 3 to get 2/6
mathstudent55
  • mathstudent55
3/3 = 1 18/3 = 6
mathstudent55
  • mathstudent55
|dw:1356660621873:dw|
mathstudent55
  • mathstudent55
Not 2/6, but sqrt(2)/6
anonymous
  • anonymous
thanks for the help!
mathstudent55
  • mathstudent55
wlcm

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