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Spartan_Of_Ares Group Title

so i need more help than i thought

  • one year ago
  • one year ago

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  1. Spartan_Of_Ares Group Title
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    Trevor is tiling his bathroom floor, which has an area that is represented as 175r5 square inches. Each tile has an area of\[64r\] . The total number of tiles used can be represented by the expression below. \[\frac{ 175r ^{5} }{ \sqrt{64r ^{17}} }\] Simplify the expression for the total number of tiles used. Show your work.

    • one year ago
  2. Spartan_Of_Ares Group Title
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    @ghazi can you help me?

    • one year ago
  3. ghazi Group Title
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    64= 8*8

    • one year ago
  4. ghazi Group Title
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    \[\frac{ 175 r^5 }{ 8 r^8 \sqrt{r} }=\frac{ 175 }{ 8r^3 \sqrt r }\]

    • one year ago
  5. ghazi Group Title
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    \[\sqrt{R^{17}}=\sqrt{R^{16}*R}=\sqrt{(R^{2})^8*R}=R \sqrt R\]

    • one year ago
  6. Spartan_Of_Ares Group Title
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    @ghazi Ummmmmm what do i do im lost

    • one year ago
  7. ghazi Group Title
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    my previous post is answer

    • one year ago
  8. ghazi Group Title
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    \[\sqrt{R^2}=R\]

    • one year ago
  9. Spartan_Of_Ares Group Title
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    can you give me a through explanation on how to solve this?

    • one year ago
  10. BrittanyFrench Group Title
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    I"m sorry, I have NO clue...

    • one year ago
  11. Spartan_Of_Ares Group Title
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    thats ok thanks anyways you get a medal for effort

    • one year ago
  12. ghazi Group Title
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    \[\frac{ R^5 }{ R^8 }=\frac{ 1 }{ R^{8-5} }=\frac{ 1 }{ R^3 }\]

    • one year ago
  13. BrittanyFrench Group Title
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    :) awh thanks..

    • one year ago
  14. ghazi Group Title
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    \[\sqrt{R^{16}}=(R^{16})^{1/2}= R^8\]

    • one year ago
  15. quarks16 Group Title
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    Wait, is that 175r^5?

    • one year ago
  16. quarks16 Group Title
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    If it is, then first you'd have to find out how many tiles that are used. (I'm sort of winging this as I go, so if I don't really make sense, then, um.... sorry.)|dw:1356665803264:dw|

    • one year ago
  17. quarks16 Group Title
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    To find out how many tiles can fit in the bathroom, divide the area of the bathroom by the area of the tile; so, 175r^5 / 64r.

    • one year ago
  18. quarks16 Group Title
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    ....where did the \[\frac{ 175r^{5} }{ \sqrt{64r ^{17}} }\] come from? Especially the 64r17...? Did I miss something somewhere?

    • one year ago
  19. quarks16 Group Title
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    Well anyways, if we go by the expression that you wrote, then first you would simplify the square root, which was what ghazi was trying to show you. Let's break down how to simplify the square root. First, split it into a part that you can find the square root of, and a part that you can't. So: \[\sqrt{64r ^{16}}\times \sqrt{r}\]

    • one year ago
  20. quarks16 Group Title
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    Now, you can simplify the first part into \[8r ^{8}\times \sqrt{r}\] which can be written as \[8r ^{8}\sqrt{r}\]

    • one year ago
  21. quarks16 Group Title
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    Now the expression looks like \[\frac{ 175r ^{5} }{8r ^{8}\sqrt{r}}\]

    • one year ago
  22. quarks16 Group Title
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    Now you can focus on the r's. In the numerator (on the top) you have r^5. In the denominator (on the bottom), you have r^8. When that happens, you can sort of cancel out a bunch of the r's. Think of it this way. \[\frac{ r \times r \times r \times r \times r \times r \times r \times r}{ r \times r \times r \times r \times r }\]

    • one year ago
  23. quarks16 Group Title
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    Oh wait. That's wrong. Switch it around. There're 8 r's on the bottom, and 5 r's on the top.

    • one year ago
  24. quarks16 Group Title
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    |dw:1356667149325:dw|

    • one year ago
  25. quarks16 Group Title
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    Now, when you cancel them out, you'll get rid of all the r's on the top, and leave 3 r's on the bottom. Like this.|dw:1356667349240:dw|

    • one year ago
  26. quarks16 Group Title
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    So now when you go back to your whole equation, you get something that looks like this:\[\frac{ 175 }{ 8r ^{3}\sqrt{r} }\]

    • one year ago
  27. quarks16 Group Title
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    ...which was what ghazi showed you. But I guess I just gave you the really long, drawn out explanation. :P

    • one year ago
  28. quarks16 Group Title
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    Hope I helped....

    • one year ago
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