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Spartan_Of_Ares

  • 2 years ago

so i need more help than i thought

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  1. Spartan_Of_Ares
    • 2 years ago
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    Trevor is tiling his bathroom floor, which has an area that is represented as 175r5 square inches. Each tile has an area of\[64r\] . The total number of tiles used can be represented by the expression below. \[\frac{ 175r ^{5} }{ \sqrt{64r ^{17}} }\] Simplify the expression for the total number of tiles used. Show your work.

  2. Spartan_Of_Ares
    • 2 years ago
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    @ghazi can you help me?

  3. ghazi
    • 2 years ago
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    64= 8*8

  4. ghazi
    • 2 years ago
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    \[\frac{ 175 r^5 }{ 8 r^8 \sqrt{r} }=\frac{ 175 }{ 8r^3 \sqrt r }\]

  5. ghazi
    • 2 years ago
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    \[\sqrt{R^{17}}=\sqrt{R^{16}*R}=\sqrt{(R^{2})^8*R}=R \sqrt R\]

  6. Spartan_Of_Ares
    • 2 years ago
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    @ghazi Ummmmmm what do i do im lost

  7. ghazi
    • 2 years ago
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    my previous post is answer

  8. ghazi
    • 2 years ago
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    \[\sqrt{R^2}=R\]

  9. Spartan_Of_Ares
    • 2 years ago
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    can you give me a through explanation on how to solve this?

  10. BrittanyFrench
    • 2 years ago
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    I"m sorry, I have NO clue...

  11. Spartan_Of_Ares
    • 2 years ago
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    thats ok thanks anyways you get a medal for effort

  12. ghazi
    • 2 years ago
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    \[\frac{ R^5 }{ R^8 }=\frac{ 1 }{ R^{8-5} }=\frac{ 1 }{ R^3 }\]

  13. BrittanyFrench
    • 2 years ago
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    :) awh thanks..

  14. ghazi
    • 2 years ago
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    \[\sqrt{R^{16}}=(R^{16})^{1/2}= R^8\]

  15. quarks16
    • 2 years ago
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    Wait, is that 175r^5?

  16. quarks16
    • 2 years ago
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    If it is, then first you'd have to find out how many tiles that are used. (I'm sort of winging this as I go, so if I don't really make sense, then, um.... sorry.)|dw:1356665803264:dw|

  17. quarks16
    • 2 years ago
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    To find out how many tiles can fit in the bathroom, divide the area of the bathroom by the area of the tile; so, 175r^5 / 64r.

  18. quarks16
    • 2 years ago
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    ....where did the \[\frac{ 175r^{5} }{ \sqrt{64r ^{17}} }\] come from? Especially the 64r17...? Did I miss something somewhere?

  19. quarks16
    • 2 years ago
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    Well anyways, if we go by the expression that you wrote, then first you would simplify the square root, which was what ghazi was trying to show you. Let's break down how to simplify the square root. First, split it into a part that you can find the square root of, and a part that you can't. So: \[\sqrt{64r ^{16}}\times \sqrt{r}\]

  20. quarks16
    • 2 years ago
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    Now, you can simplify the first part into \[8r ^{8}\times \sqrt{r}\] which can be written as \[8r ^{8}\sqrt{r}\]

  21. quarks16
    • 2 years ago
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    Now the expression looks like \[\frac{ 175r ^{5} }{8r ^{8}\sqrt{r}}\]

  22. quarks16
    • 2 years ago
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    Now you can focus on the r's. In the numerator (on the top) you have r^5. In the denominator (on the bottom), you have r^8. When that happens, you can sort of cancel out a bunch of the r's. Think of it this way. \[\frac{ r \times r \times r \times r \times r \times r \times r \times r}{ r \times r \times r \times r \times r }\]

  23. quarks16
    • 2 years ago
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    Oh wait. That's wrong. Switch it around. There're 8 r's on the bottom, and 5 r's on the top.

  24. quarks16
    • 2 years ago
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    |dw:1356667149325:dw|

  25. quarks16
    • 2 years ago
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    Now, when you cancel them out, you'll get rid of all the r's on the top, and leave 3 r's on the bottom. Like this.|dw:1356667349240:dw|

  26. quarks16
    • 2 years ago
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    So now when you go back to your whole equation, you get something that looks like this:\[\frac{ 175 }{ 8r ^{3}\sqrt{r} }\]

  27. quarks16
    • 2 years ago
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    ...which was what ghazi showed you. But I guess I just gave you the really long, drawn out explanation. :P

  28. quarks16
    • 2 years ago
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    Hope I helped....

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