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Spartan_Of_Ares

  • one year ago

so i need more help than i thought

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  1. Spartan_Of_Ares
    • one year ago
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    Trevor is tiling his bathroom floor, which has an area that is represented as 175r5 square inches. Each tile has an area of\[64r\] . The total number of tiles used can be represented by the expression below. \[\frac{ 175r ^{5} }{ \sqrt{64r ^{17}} }\] Simplify the expression for the total number of tiles used. Show your work.

  2. Spartan_Of_Ares
    • one year ago
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    @ghazi can you help me?

  3. ghazi
    • one year ago
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    64= 8*8

  4. ghazi
    • one year ago
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    \[\frac{ 175 r^5 }{ 8 r^8 \sqrt{r} }=\frac{ 175 }{ 8r^3 \sqrt r }\]

  5. ghazi
    • one year ago
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    \[\sqrt{R^{17}}=\sqrt{R^{16}*R}=\sqrt{(R^{2})^8*R}=R \sqrt R\]

  6. Spartan_Of_Ares
    • one year ago
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    @ghazi Ummmmmm what do i do im lost

  7. ghazi
    • one year ago
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    my previous post is answer

  8. ghazi
    • one year ago
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    \[\sqrt{R^2}=R\]

  9. Spartan_Of_Ares
    • one year ago
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    can you give me a through explanation on how to solve this?

  10. BrittanyFrench
    • one year ago
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    I"m sorry, I have NO clue...

  11. Spartan_Of_Ares
    • one year ago
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    thats ok thanks anyways you get a medal for effort

  12. ghazi
    • one year ago
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    \[\frac{ R^5 }{ R^8 }=\frac{ 1 }{ R^{8-5} }=\frac{ 1 }{ R^3 }\]

  13. BrittanyFrench
    • one year ago
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    :) awh thanks..

  14. ghazi
    • one year ago
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    \[\sqrt{R^{16}}=(R^{16})^{1/2}= R^8\]

  15. quarks16
    • one year ago
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    Wait, is that 175r^5?

  16. quarks16
    • one year ago
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    If it is, then first you'd have to find out how many tiles that are used. (I'm sort of winging this as I go, so if I don't really make sense, then, um.... sorry.)|dw:1356665803264:dw|

  17. quarks16
    • one year ago
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    To find out how many tiles can fit in the bathroom, divide the area of the bathroom by the area of the tile; so, 175r^5 / 64r.

  18. quarks16
    • one year ago
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    ....where did the \[\frac{ 175r^{5} }{ \sqrt{64r ^{17}} }\] come from? Especially the 64r17...? Did I miss something somewhere?

  19. quarks16
    • one year ago
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    Well anyways, if we go by the expression that you wrote, then first you would simplify the square root, which was what ghazi was trying to show you. Let's break down how to simplify the square root. First, split it into a part that you can find the square root of, and a part that you can't. So: \[\sqrt{64r ^{16}}\times \sqrt{r}\]

  20. quarks16
    • one year ago
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    Now, you can simplify the first part into \[8r ^{8}\times \sqrt{r}\] which can be written as \[8r ^{8}\sqrt{r}\]

  21. quarks16
    • one year ago
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    Now the expression looks like \[\frac{ 175r ^{5} }{8r ^{8}\sqrt{r}}\]

  22. quarks16
    • one year ago
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    Now you can focus on the r's. In the numerator (on the top) you have r^5. In the denominator (on the bottom), you have r^8. When that happens, you can sort of cancel out a bunch of the r's. Think of it this way. \[\frac{ r \times r \times r \times r \times r \times r \times r \times r}{ r \times r \times r \times r \times r }\]

  23. quarks16
    • one year ago
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    Oh wait. That's wrong. Switch it around. There're 8 r's on the bottom, and 5 r's on the top.

  24. quarks16
    • one year ago
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    |dw:1356667149325:dw|

  25. quarks16
    • one year ago
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    Now, when you cancel them out, you'll get rid of all the r's on the top, and leave 3 r's on the bottom. Like this.|dw:1356667349240:dw|

  26. quarks16
    • one year ago
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    So now when you go back to your whole equation, you get something that looks like this:\[\frac{ 175 }{ 8r ^{3}\sqrt{r} }\]

  27. quarks16
    • one year ago
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    ...which was what ghazi showed you. But I guess I just gave you the really long, drawn out explanation. :P

  28. quarks16
    • one year ago
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    Hope I helped....

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