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sha0403

  • 3 years ago

event A and B in a sample space S have the following probabilities. P(A)=0.4,P(B')=0.3 and P(A intersect B)=0.2... Help me to find number of sample space?

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  1. srossd
    • 3 years ago
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    What do you mean by "number of sample space"?

  2. sha0403
    • 3 years ago
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    did u know abt it n(s) in probabilitty? that include all the value of data..

  3. srossd
    • 3 years ago
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    Oh, cardinal number. Generally, you would need more info than that to figure out the cardinal number exactly, but the minimum possible would be 10, I think.

  4. srossd
    • 3 years ago
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    Oh oh ohhhh nevermind. Disregard everything I"ve said so far, I get it now.

  5. srossd
    • 3 years ago
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    So P(B) is 0.3, P(A) = 0.4...wait a minute, those can't be the only events, right?

  6. srossd
    • 3 years ago
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    And just noticed it was P(B'), so P(B) is 0.7, which is even worse :/.

  7. sha0403
    • 3 years ago
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    so,how we identified the n(s)?

  8. srossd
    • 3 years ago
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    Ok, actually, lets say they're not mutually exclusive events (normally that would be explicit, but oh well). So say A contains 4 events, and B contains 7. Their intersection contains 2. So there are 9 events: 4+7-2. Of course, it could be any multiple of 9 too.

  9. sha0403
    • 3 years ago
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    you mean n(s) is 9?

  10. srossd
    • 3 years ago
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    Yeah, n(S)=9, I think that's what they're going for. Sorry I'm not exactly an expert here, but no one else is backing me up, so that's my best guess.

  11. sha0403
    • 3 years ago
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    oh i think that 9 at first but i'm not confident..but after u say that,, i confident now..thank u very much k.. =)

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