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Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.5\[\frac{dv}{dt} = 60t  4v\] \[\frac{dv}{dt} + 4v = 60t\] so find the integratiing factor \[ u = e^\int{4v}\]

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Woops the integrating factor should be,\[\huge u=e^{\int\limits 4 dt}\] Without that silly v there.

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.5\[\frac{dv}{dt} \left(e^{4t}\right) + 4\left(e^{4t}\right) v= 60t(e^{4t}) \] \[\frac{dv}{dt} \left(e^{4t}\right) +\left(e^{4t}\right)'v =60t\left(e^{4t}\right) \] \[\left(e^{4t}v\right) '= 60t\left(e^{4t}\right) \] Integrate both sides. \[\int\limits\left(e^{4t}v\right) ' = \int\limits60t\left(e^{4t}\right) dt\] You should be able to do it now.

jychay2
 2 years ago
Best ResponseYou've already chosen the best response.0Alright, I get it.Thx ^^
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