anonymous
  • anonymous
In acceleration vs time grapg of a Particle covering a distance of 40m from t=2 till t=4s The magnitude of Velocity at t= 10s
Physics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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ajprincess
  • ajprincess
I am nt sure if this is right. Using s=ut+1/2at^2 40=2u+1/2*5*4 40=2u+10 2u=40-10 2u=30 u=30/2 u=15 using v=u+at v=15+5*2 v=15+10 v=25 The area
anonymous
  • anonymous
25 + 15 = 40

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anonymous
  • anonymous
right ?
anonymous
  • anonymous
1/2 * 5 * 6 = 15
ajprincess
  • ajprincess
yup:)
anonymous
  • anonymous
but @ajprincess i want to know why Area under this Graph results in 30 m/s
ajprincess
  • ajprincess
It is not given that the particle starts from rest. so it might have had an initial velocity. From the graph acc is only zero at first nt the velocity.
ajprincess
  • ajprincess
does that make sense @yahoo?
anonymous
  • anonymous
What exactly are you supposed to find ?
ajprincess
  • ajprincess
The magnitude of Velocity at t= 10s
anonymous
  • anonymous
thxxx
ajprincess
  • ajprincess
welcome:)

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