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In acceleration vs time grapg of a Particle covering a distance of 40m from t=2 till t=4s The magnitude of Velocity at t= 10s
 one year ago
 one year ago
Yahoo! Group Title
In acceleration vs time grapg of a Particle covering a distance of 40m from t=2 till t=4s The magnitude of Velocity at t= 10s
 one year ago
 one year ago

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Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
dw:1356701933177:dw
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
I am nt sure if this is right. Using s=ut+1/2at^2 40=2u+1/2*5*4 40=2u+10 2u=4010 2u=30 u=30/2 u=15 using v=u+at v=15+5*2 v=15+10 v=25 The area
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
25 + 15 = 40
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
1/2 * 5 * 6 = 15
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
but @ajprincess i want to know why Area under this Graph results in 30 m/s
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
It is not given that the particle starts from rest. so it might have had an initial velocity. From the graph acc is only zero at first nt the velocity.
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
does that make sense @yahoo?
 one year ago

Aditi_Singh Group TitleBest ResponseYou've already chosen the best response.0
What exactly are you supposed to find ?
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
The magnitude of Velocity at t= 10s
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
welcome:)
 one year ago
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