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In acceleration vs time grapg of a Particle covering a distance of 40m from t=2 till t=4s The magnitude of Velocity at t= 10s
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|dw:1356701933177:dw|
ajprincess
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I am nt sure if this is right.
Using s=ut+1/2at^2
40=2u+1/2*5*4
40=2u+10
2u=40-10
2u=30
u=30/2
u=15
using v=u+at
v=15+5*2
v=15+10
v=25
The area
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25 + 15 = 40
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right ?
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1/2 * 5 * 6 = 15
ajprincess
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yup:)
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but @ajprincess i want to know why Area under this Graph results in 30 m/s
ajprincess
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It is not given that the particle starts from rest. so it might have had an initial velocity. From the graph acc is only zero at first nt the velocity.
ajprincess
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does that make sense @yahoo?
Aditi_Singh
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What exactly are you supposed to find ?
ajprincess
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The magnitude of Velocity at t= 10s
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thxxx
ajprincess
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welcome:)