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In acceleration vs time grapg of a Particle covering a distance of 40m from t=2 till t=4s The magnitude of Velocity at t= 10s

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I am nt sure if this is right. Using s=ut+1/2at^2 40=2u+1/2*5*4 40=2u+10 2u=40-10 2u=30 u=30/2 u=15 using v=u+at v=15+5*2 v=15+10 v=25 The area
25 + 15 = 40

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Other answers:

right ?
1/2 * 5 * 6 = 15
but @ajprincess i want to know why Area under this Graph results in 30 m/s
It is not given that the particle starts from rest. so it might have had an initial velocity. From the graph acc is only zero at first nt the velocity.
does that make sense @yahoo?
What exactly are you supposed to find ?
The magnitude of Velocity at t= 10s

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