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Yahoo!

  • 3 years ago

In acceleration vs time grapg of a Particle covering a distance of 40m from t=2 till t=4s The magnitude of Velocity at t= 10s

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  1. Yahoo!
    • 3 years ago
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    |dw:1356701933177:dw|

  2. ajprincess
    • 3 years ago
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    I am nt sure if this is right. Using s=ut+1/2at^2 40=2u+1/2*5*4 40=2u+10 2u=40-10 2u=30 u=30/2 u=15 using v=u+at v=15+5*2 v=15+10 v=25 The area

  3. Yahoo!
    • 3 years ago
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    25 + 15 = 40

  4. Yahoo!
    • 3 years ago
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    right ?

  5. Yahoo!
    • 3 years ago
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    1/2 * 5 * 6 = 15

  6. ajprincess
    • 3 years ago
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    yup:)

  7. Yahoo!
    • 3 years ago
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    but @ajprincess i want to know why Area under this Graph results in 30 m/s

  8. ajprincess
    • 3 years ago
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    It is not given that the particle starts from rest. so it might have had an initial velocity. From the graph acc is only zero at first nt the velocity.

  9. ajprincess
    • 3 years ago
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    does that make sense @yahoo?

  10. Aditi_Singh
    • 3 years ago
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    What exactly are you supposed to find ?

  11. ajprincess
    • 3 years ago
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    The magnitude of Velocity at t= 10s

  12. Yahoo!
    • 3 years ago
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    thxxx

  13. ajprincess
    • 3 years ago
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    welcome:)

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