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 one year ago
pete and sean decide to raise money for a charity by having a carnival in their backyard. in one of the games that they set up, the probability that a person will win is 0.4. if robyn plays that game nine times, what is the probability that she wins exactly four times?
A)9C5^5 (0.4)^5 (0.4)^5
B)9C4 (0.5)^4 (0.5)^5
C) 9C4 (0.4)^4 (0.6)^5
D)9C5 (0.4)^5 (0.6)^4
and how did you get really confused on probability formula thx
 one year ago
pete and sean decide to raise money for a charity by having a carnival in their backyard. in one of the games that they set up, the probability that a person will win is 0.4. if robyn plays that game nine times, what is the probability that she wins exactly four times? A)9C5^5 (0.4)^5 (0.4)^5 B)9C4 (0.5)^4 (0.5)^5 C) 9C4 (0.4)^4 (0.6)^5 D)9C5 (0.4)^5 (0.6)^4 and how did you get really confused on probability formula thx

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SeemsBeauteos
 one year ago
Best ResponseYou've already chosen the best response.0oh it's suppose to be 9C5 (0.4)^5 (0.4)^4 sorry

Stiwan
 one year ago
Best ResponseYou've already chosen the best response.0the answer anyway is \[(0,4)^4 * (0,6)^5 * \frac{ 9! }{ 4!5! }\] where (0.4) is the probability to win and (0.6) is 1  0.4 equals the probability to lose. Do you need more explanations why this is the answer?

Stiwan
 one year ago
Best ResponseYou've already chosen the best response.0I guess 9C4 means \[\left(\begin{matrix}9 \\ 4\end{matrix}\right) = \frac{ 9! }{ 4!5! }\] then answer C is equivalent to my solution

SeemsBeauteos
 one year ago
Best ResponseYou've already chosen the best response.0why do you substract it by 1

Stiwan
 one year ago
Best ResponseYou've already chosen the best response.0well, what does the probability of 1 mean? It means that the case you're looking at is going to happen EVERY time (100% of the tries). Let p be the probability to win, and q be the probability to lose. In this game we assume that anytime you play, you either win or lose. This OR translates into the language of probability as a '+', that means p+q = 1. Because when you look at all possible cases and add them , that is equivalent to calculating the probability of one of the possible cases happening  which happens 100% of the time, hence the probability is 1. In this example, you the probability to win (p) and the probability to lose (q) are all the possible cases, hence p + q = 1 ==> q = 1p

SeemsBeauteos
 one year ago
Best ResponseYou've already chosen the best response.0okay what do the exponents represents

Stiwan
 one year ago
Best ResponseYou've already chosen the best response.0They're kind of the translation of 'AND' into the language of probability. For example, if you tried once to win the game you had a probability of 0.4. If you tried twice, the probability to win twice would be (0.4) * (0.4) = (0.4)^2. The probability to play 9 times and win 9 games would be (0.4)^9 Similarly, if you played 5 times and lost all 5 games the probability for that would be (0.6)^5 Can you see the scheme here?

SeemsBeauteos
 one year ago
Best ResponseYou've already chosen the best response.0yeah! okay that pretty much sums most of my confusion thank you so much!
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