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DorelTibi
Group Title
Triangle ABD is congruent to triangle CBD
http://curriculum.kcdistancelearning.com/courses/GEOMxHSA09/a/assessments/TTrianglesUnitExam/Geometry_Unit4_Exam_36f1.gif
 one year ago
 one year ago
DorelTibi Group Title
Triangle ABD is congruent to triangle CBD http://curriculum.kcdistancelearning.com/courses/GEOMxHSA09/a/assessments/TTrianglesUnitExam/Geometry_Unit4_Exam_36f1.gif
 one year ago
 one year ago

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DorelTibi Group TitleBest ResponseYou've already chosen the best response.0
true or false? Help me Plz!!!
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
If two triangles have two angles and the included side congruent, the triangles are congruent. ASA (anglesideangle).
 one year ago

DorelTibi Group TitleBest ResponseYou've already chosen the best response.0
so Its true
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
Explain why it is true.
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.1
The triangles are congruent but not by ASA.
 one year ago

DorelTibi Group TitleBest ResponseYou've already chosen the best response.0
Because it is a theorem
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.1
Which ways of proving two triangles congruent do you know?
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
@methstudent55: if two triangles have two angle congruent, the third is also congruent.
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
@mathstudent55: if two triangles have two angle congruent, the third is also congruent. It is not SAS because we only have one common side, and we do not know congruence of the other sides.
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.1
@mathmate You're correct. You can do it by ASA by first stating that the third angles are congruent, but there is a quicker way of doing it that does not require that extra step.
 one year ago

DorelTibi Group TitleBest ResponseYou've already chosen the best response.0
WAIT so its true
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
It still takes an extra step.
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.1
There is a way that just by looking you can immediately conclude the triangles are congruent with out any extra steps.
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
To prove by SAS, you need to show that one other pair of sides are congruent.
 one year ago

DorelTibi Group TitleBest ResponseYou've already chosen the best response.0
o its false because not much information, right?
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
@ DorelTibi: sorry that we are discussing the semantics of things, but are you able to show that the triangles are congruent?
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.1
It's not SAS. We don't have info on two sides. We only know about the side in common.
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.1
Here it is: AAS. If two angles of a triangle and a not included side are congruent to corresponding parts of another triangle, the triangles are congruent.
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
In fact, AAS is the equivalent of ASA, since when two angles are congruent, then congruence of any other corresponding side is sufficient to show congruence. Equivalence means that all AAS cases can be shown to be ASA and viceversa.
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.1
Indeed, AAS is easier.
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.1
In the end, if you do it by ASA, you need to show BD is congr to itself and <s CDB and ADB are congruent. If you do it by AAS, you only need to show BD is congr to itself. So either way you need one extra step or two extra steps before the conlcusion.
 one year ago
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