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ksaimouli

  • 2 years ago

find g(-1) and g''(-1)

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  1. ksaimouli
    • 2 years ago
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    |dw:1356718690979:dw|

  2. ksaimouli
    • 2 years ago
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    \[g(x)=\int\limits_{0}^{x}f(t) dt\]

  3. ksaimouli
    • 2 years ago
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    graph above is f

  4. ksaimouli
    • 2 years ago
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    |dw:1356718836761:dw|

  5. ksaimouli
    • 2 years ago
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    find g(-1)

  6. ksaimouli
    • 2 years ago
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    @hartnn

  7. hartnn
    • 2 years ago
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    can u find the point of intersection of those 2 lines ? or, equation of those lines ??

  8. mathmate
    • 2 years ago
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    Is g(x) a constant? I don't see x in the definition of g(x). Does f(x) = 0 for x>2, or does it decrease forever?

  9. ksaimouli
    • 2 years ago
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    @hba

  10. ksaimouli
    • 2 years ago
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    i know that f'(-1)=0

  11. ksaimouli
    • 2 years ago
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    what i have no idea how to find the f(-1)

  12. hartnn
    • 2 years ago
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    |dw:1356720077842:dw|

  13. ksaimouli
    • 2 years ago
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    slope is 3

  14. hba
    • 2 years ago
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    Now you can find the equation :)

  15. hartnn
    • 2 years ago
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    and u also have point , so equation is ?

  16. ksaimouli
    • 2 years ago
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    y=3x+3

  17. hartnn
    • 2 years ago
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    x=-1 thats your f(t) for 0 to -1

  18. hartnn
    • 2 years ago
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    \(g(-1)=\int\limits_{0}^{-1}(3x+3) dt\)

  19. hartnn
    • 2 years ago
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    can u find g(-1) now

  20. ksaimouli
    • 2 years ago
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    yes

  21. hartnn
    • 2 years ago
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    good :)

  22. hba
    • 2 years ago
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    -(3x+3)

  23. ksaimouli
    • 2 years ago
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    -3/2

  24. ksaimouli
    • 2 years ago
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    what about f''(-1)

  25. hartnn
    • 2 years ago
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    u sure about -3/2 ??

  26. ksaimouli
    • 2 years ago
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    yes

  27. ksaimouli
    • 2 years ago
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    |dw:1356720626985:dw|

  28. hartnn
    • 2 years ago
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    ok, \(g'(x)=(d/dx)\int_0^xf(t)dt = f(x)\\so,g''(x)=f'(x)\\g"(-1)=f(-1)\) can u find f(-1) ?? and no

  29. ksaimouli
    • 2 years ago
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    why not

  30. hartnn
    • 2 years ago
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    why ?

  31. hartnn
    • 2 years ago
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    why u want to use that line ?? f(-1) is simple..

  32. ksaimouli
    • 2 years ago
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    ok

  33. ksaimouli
    • 2 years ago
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    0

  34. hartnn
    • 2 years ago
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    yes, correct.

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