hba
  • hba
A particle moves along x-axis.It starts from rest at origin O and its acceleration after t sec is given by a=3-t . Calculate the displacment from O when it is at rest.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
hba
  • hba
@saifoo.khan
hba
  • hba
Can you do it ?
jennychan12
  • jennychan12
find antiderivative twice for a = 3-t

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More answers

saifoo.khan
  • saifoo.khan
integrate. a=3-t v = 3t - t^2/2 + C Now set it equal to zero to get time. Then integrate again, find the disp.
hba
  • hba
Therefore, the answer is 18. Something which appeared in the (NUST) test.
hba
  • hba
@saifoo.khan
saifoo.khan
  • saifoo.khan
REALLY? O_O
hba
  • hba
Yeah
saifoo.khan
  • saifoo.khan
An O'levels student who have Add math can solve this too! D: D: D:
hba
  • hba
Hmm,good :)
hba
  • hba
What about hyperbolic functions ? You've done that ?
saifoo.khan
  • saifoo.khan
give me the problem, then i can tlel.
hba
  • hba
\[\int\limits_{}^{}e^x[\sinh^{-1} x+\frac{ 1 }{ \sqrt{1+x^2} }]dx=\]
hba
  • hba
@saifoo.khan Like this.
saifoo.khan
  • saifoo.khan
INtegration by parts?
saifoo.khan
  • saifoo.khan
idk how to deal with sinh^-1
hba
  • hba
So you don't know hyperbolic functions ?
experimentX
  • experimentX
use e^x(f(x) + f'(x)) rule differentiation of arcsinh(x) = 1/sqrt(...)
saifoo.khan
  • saifoo.khan
I guess no, then. :S
hba
  • hba
hmm No need to worry about that it's easy,you can do that later. What about finding the area from a diag ?
saifoo.khan
  • saifoo.khan
We have to learn that parallelogram thing. But i can find the area/vol of a curve and stuff
hba
  • hba
Lets see. find the Area A+B |dw:1356722864399:dw|
saifoo.khan
  • saifoo.khan
NOOO! Give me more difficult one.
hba
  • hba
Ok.
hba
  • hba
find the area A |dw:1356723204131:dw|
saifoo.khan
  • saifoo.khan
|dw:1356723438919:dw|
saifoo.khan
  • saifoo.khan
Let me grab a pen and paper.
hba
  • hba
Hmm :)
saifoo.khan
  • saifoo.khan
Is calc allowed?
hba
  • hba
No not allowed+You changed the question lol :P
saifoo.khan
  • saifoo.khan
Sinx graph starts from zero. lol.
hba
  • hba
Oh okay then :/
saifoo.khan
  • saifoo.khan
Haha.
hba
  • hba
Now solve it .
saifoo.khan
  • saifoo.khan
isk what's sin(pi/4). i can only solve with the help of calc.
hba
  • hba
180/4
saifoo.khan
  • saifoo.khan
area under cos is 1/sqrt2
hba
  • hba
Sin45=0.707
saifoo.khan
  • saifoo.khan
0.707-0.293 ?
hba
  • hba
@saifoo.khan Solve it and let me know :)
saifoo.khan
  • saifoo.khan
0.414
hba
  • hba
Don't do it in decimals.
saifoo.khan
  • saifoo.khan
dang.
saifoo.khan
  • saifoo.khan
1/sqrt2 - (-1+sqrt2)/sqrt2
saifoo.khan
  • saifoo.khan
Making: (2-sqrt2)/sqrt2
saifoo.khan
  • saifoo.khan
Making: \[\frac{2\sqrt2-2}{2}\]
saifoo.khan
  • saifoo.khan
sqrt2-1 final answer?
hba
  • hba
\[\sqrt{2}-1 \ sq.unit\] Yeah right :D
saifoo.khan
  • saifoo.khan
Wheo! B)
hba
  • hba
One more. Find the area enclosed by x=y^2 and y=x-2
saifoo.khan
  • saifoo.khan
umm okay. solving.
hba
  • hba
k.
saifoo.khan
  • saifoo.khan
1,4
saifoo.khan
  • saifoo.khan
area under line = 2 squnits
saifoo.khan
  • saifoo.khan
trying to figure out about x=y^2
saifoo.khan
  • saifoo.khan
1/2 final answer?
hba
  • hba
Let me give you options lol A)9/2 sq.units B)9/4 // C)9/7 // D)7/9 // E)4/9 //
saifoo.khan
  • saifoo.khan
Can't fig out.
hba
  • hba
I also couldn't figure this out lol :P
hba
  • hba
@hartnn Can you solve it ?
hba
  • hba
Find the area enclosed by x=y^2 and y=x-2
hartnn
  • hartnn
this is double integration problem.. right ?
hba
  • hba
i don't think so.
hartnn
  • hartnn
plot both curves..
saifoo.khan
  • saifoo.khan
|dw:1356725537575:dw|
hba
  • hba
@hartnn Yes ?
hartnn
  • hartnn
sorry, got disconnected.
hartnn
  • hartnn
|dw:1356727367179:dw| \(\int \limits_{y_1}^{y_2}f_1(x)-f_2(x)=\int \limits_{y_1}^{y_2}(y+2)-y^2dy|dw:1356727499321:dw|\)
hartnn
  • hartnn
\(\int \limits_{y_1}^{y_2}f_1(x)-f_2(x)=\int \limits_{y_1}^{y_2}(y+2)-y^2dy\)
hartnn
  • hartnn
find y2 and solve the integral
hartnn
  • hartnn
sorry, y1 and y2 limits should be |dw:1356727654740:dw|

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