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 2 years ago
A particle moves along xaxis.It starts from rest at origin O and its acceleration after t sec is given by a=3t . Calculate the displacment from O when it is at rest.
 2 years ago
A particle moves along xaxis.It starts from rest at origin O and its acceleration after t sec is given by a=3t . Calculate the displacment from O when it is at rest.

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jennychan12
 2 years ago
Best ResponseYou've already chosen the best response.1find antiderivative twice for a = 3t

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2integrate. a=3t v = 3t  t^2/2 + C Now set it equal to zero to get time. Then integrate again, find the disp.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Therefore, the answer is 18. Something which appeared in the (NUST) test.

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2An O'levels student who have Add math can solve this too! D: D: D:

hba
 2 years ago
Best ResponseYou've already chosen the best response.1What about hyperbolic functions ? You've done that ?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2give me the problem, then i can tlel.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{}e^x[\sinh^{1} x+\frac{ 1 }{ \sqrt{1+x^2} }]dx=\]

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2INtegration by parts?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2idk how to deal with sinh^1

hba
 2 years ago
Best ResponseYou've already chosen the best response.1So you don't know hyperbolic functions ?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1use e^x(f(x) + f'(x)) rule differentiation of arcsinh(x) = 1/sqrt(...)

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2I guess no, then. :S

hba
 2 years ago
Best ResponseYou've already chosen the best response.1hmm No need to worry about that it's easy,you can do that later. What about finding the area from a diag ?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2We have to learn that parallelogram thing. But i can find the area/vol of a curve and stuff

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Lets see. find the Area A+B dw:1356722864399:dw

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2NOOO! Give me more difficult one.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1find the area A dw:1356723204131:dw

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1356723438919:dw

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2Let me grab a pen and paper.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1No not allowed+You changed the question lol :P

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2Sinx graph starts from zero. lol.

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2isk what's sin(pi/4). i can only solve with the help of calc.

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2area under cos is 1/sqrt2

hba
 2 years ago
Best ResponseYou've already chosen the best response.1@saifoo.khan Solve it and let me know :)

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.21/sqrt2  (1+sqrt2)/sqrt2

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2Making: (2sqrt2)/sqrt2

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2Making: \[\frac{2\sqrt22}{2}\]

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2sqrt21 final answer?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{2}1 \ sq.unit\] Yeah right :D

hba
 2 years ago
Best ResponseYou've already chosen the best response.1One more. Find the area enclosed by x=y^2 and y=x2

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2area under line = 2 squnits

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2trying to figure out about x=y^2

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Let me give you options lol A)9/2 sq.units B)9/4 // C)9/7 // D)7/9 // E)4/9 //

hba
 2 years ago
Best ResponseYou've already chosen the best response.1I also couldn't figure this out lol :P

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Find the area enclosed by x=y^2 and y=x2

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1this is double integration problem.. right ?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1356725537575:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1sorry, got disconnected.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1356727367179:dw \(\int \limits_{y_1}^{y_2}f_1(x)f_2(x)=\int \limits_{y_1}^{y_2}(y+2)y^2dydw:1356727499321:dw\)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\int \limits_{y_1}^{y_2}f_1(x)f_2(x)=\int \limits_{y_1}^{y_2}(y+2)y^2dy\)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1find y2 and solve the integral

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1sorry, y1 and y2 limits should be dw:1356727654740:dw
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