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 one year ago
A particle moves along xaxis.It starts from rest at origin O and its acceleration after t sec is given by a=3t . Calculate the displacment from O when it is at rest.
 one year ago
A particle moves along xaxis.It starts from rest at origin O and its acceleration after t sec is given by a=3t . Calculate the displacment from O when it is at rest.

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jennychan12
 one year ago
Best ResponseYou've already chosen the best response.1find antiderivative twice for a = 3t

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2integrate. a=3t v = 3t  t^2/2 + C Now set it equal to zero to get time. Then integrate again, find the disp.

hba
 one year ago
Best ResponseYou've already chosen the best response.1Therefore, the answer is 18. Something which appeared in the (NUST) test.

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2An O'levels student who have Add math can solve this too! D: D: D:

hba
 one year ago
Best ResponseYou've already chosen the best response.1What about hyperbolic functions ? You've done that ?

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2give me the problem, then i can tlel.

hba
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{}e^x[\sinh^{1} x+\frac{ 1 }{ \sqrt{1+x^2} }]dx=\]

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2INtegration by parts?

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2idk how to deal with sinh^1

hba
 one year ago
Best ResponseYou've already chosen the best response.1So you don't know hyperbolic functions ?

experimentX
 one year ago
Best ResponseYou've already chosen the best response.1use e^x(f(x) + f'(x)) rule differentiation of arcsinh(x) = 1/sqrt(...)

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2I guess no, then. :S

hba
 one year ago
Best ResponseYou've already chosen the best response.1hmm No need to worry about that it's easy,you can do that later. What about finding the area from a diag ?

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2We have to learn that parallelogram thing. But i can find the area/vol of a curve and stuff

hba
 one year ago
Best ResponseYou've already chosen the best response.1Lets see. find the Area A+B dw:1356722864399:dw

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2NOOO! Give me more difficult one.

hba
 one year ago
Best ResponseYou've already chosen the best response.1find the area A dw:1356723204131:dw

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2dw:1356723438919:dw

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2Let me grab a pen and paper.

hba
 one year ago
Best ResponseYou've already chosen the best response.1No not allowed+You changed the question lol :P

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2Sinx graph starts from zero. lol.

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2isk what's sin(pi/4). i can only solve with the help of calc.

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2area under cos is 1/sqrt2

hba
 one year ago
Best ResponseYou've already chosen the best response.1@saifoo.khan Solve it and let me know :)

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.21/sqrt2  (1+sqrt2)/sqrt2

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2Making: (2sqrt2)/sqrt2

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2Making: \[\frac{2\sqrt22}{2}\]

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2sqrt21 final answer?

hba
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{2}1 \ sq.unit\] Yeah right :D

hba
 one year ago
Best ResponseYou've already chosen the best response.1One more. Find the area enclosed by x=y^2 and y=x2

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2umm okay. solving.

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2area under line = 2 squnits

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2trying to figure out about x=y^2

hba
 one year ago
Best ResponseYou've already chosen the best response.1Let me give you options lol A)9/2 sq.units B)9/4 // C)9/7 // D)7/9 // E)4/9 //

hba
 one year ago
Best ResponseYou've already chosen the best response.1I also couldn't figure this out lol :P

hba
 one year ago
Best ResponseYou've already chosen the best response.1@hartnn Can you solve it ?

hba
 one year ago
Best ResponseYou've already chosen the best response.1Find the area enclosed by x=y^2 and y=x2

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1this is double integration problem.. right ?

saifoo.khan
 one year ago
Best ResponseYou've already chosen the best response.2dw:1356725537575:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1sorry, got disconnected.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1dw:1356727367179:dw \(\int \limits_{y_1}^{y_2}f_1(x)f_2(x)=\int \limits_{y_1}^{y_2}(y+2)y^2dydw:1356727499321:dw\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\int \limits_{y_1}^{y_2}f_1(x)f_2(x)=\int \limits_{y_1}^{y_2}(y+2)y^2dy\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1find y2 and solve the integral

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1sorry, y1 and y2 limits should be dw:1356727654740:dw
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