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A particle moves along xaxis.It starts from rest at origin O and its acceleration after t sec is given by a=3t . Calculate the displacment from O when it is at rest.
 one year ago
 one year ago
A particle moves along xaxis.It starts from rest at origin O and its acceleration after t sec is given by a=3t . Calculate the displacment from O when it is at rest.
 one year ago
 one year ago

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jennychan12Best ResponseYou've already chosen the best response.1
find antiderivative twice for a = 3t
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
integrate. a=3t v = 3t  t^2/2 + C Now set it equal to zero to get time. Then integrate again, find the disp.
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Therefore, the answer is 18. Something which appeared in the (NUST) test.
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
An O'levels student who have Add math can solve this too! D: D: D:
 one year ago

hbaBest ResponseYou've already chosen the best response.1
What about hyperbolic functions ? You've done that ?
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
give me the problem, then i can tlel.
 one year ago

hbaBest ResponseYou've already chosen the best response.1
\[\int\limits_{}^{}e^x[\sinh^{1} x+\frac{ 1 }{ \sqrt{1+x^2} }]dx=\]
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
INtegration by parts?
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
idk how to deal with sinh^1
 one year ago

hbaBest ResponseYou've already chosen the best response.1
So you don't know hyperbolic functions ?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
use e^x(f(x) + f'(x)) rule differentiation of arcsinh(x) = 1/sqrt(...)
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
I guess no, then. :S
 one year ago

hbaBest ResponseYou've already chosen the best response.1
hmm No need to worry about that it's easy,you can do that later. What about finding the area from a diag ?
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
We have to learn that parallelogram thing. But i can find the area/vol of a curve and stuff
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Lets see. find the Area A+B dw:1356722864399:dw
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
NOOO! Give me more difficult one.
 one year ago

hbaBest ResponseYou've already chosen the best response.1
find the area A dw:1356723204131:dw
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
dw:1356723438919:dw
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Let me grab a pen and paper.
 one year ago

hbaBest ResponseYou've already chosen the best response.1
No not allowed+You changed the question lol :P
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Sinx graph starts from zero. lol.
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
isk what's sin(pi/4). i can only solve with the help of calc.
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
area under cos is 1/sqrt2
 one year ago

hbaBest ResponseYou've already chosen the best response.1
@saifoo.khan Solve it and let me know :)
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
1/sqrt2  (1+sqrt2)/sqrt2
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Making: (2sqrt2)/sqrt2
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Making: \[\frac{2\sqrt22}{2}\]
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
sqrt21 final answer?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
\[\sqrt{2}1 \ sq.unit\] Yeah right :D
 one year ago

hbaBest ResponseYou've already chosen the best response.1
One more. Find the area enclosed by x=y^2 and y=x2
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
umm okay. solving.
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
area under line = 2 squnits
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
trying to figure out about x=y^2
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Let me give you options lol A)9/2 sq.units B)9/4 // C)9/7 // D)7/9 // E)4/9 //
 one year ago

hbaBest ResponseYou've already chosen the best response.1
I also couldn't figure this out lol :P
 one year ago

hbaBest ResponseYou've already chosen the best response.1
@hartnn Can you solve it ?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Find the area enclosed by x=y^2 and y=x2
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
this is double integration problem.. right ?
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
dw:1356725537575:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
sorry, got disconnected.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
dw:1356727367179:dw \(\int \limits_{y_1}^{y_2}f_1(x)f_2(x)=\int \limits_{y_1}^{y_2}(y+2)y^2dydw:1356727499321:dw\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\int \limits_{y_1}^{y_2}f_1(x)f_2(x)=\int \limits_{y_1}^{y_2}(y+2)y^2dy\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
find y2 and solve the integral
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
sorry, y1 and y2 limits should be dw:1356727654740:dw
 one year ago
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