nee5277 Group Title Someone please help me to study for my test with this review packet!! :) one year ago one year ago

1. tictac4456 Group Title

ill help or shall i say ill try

2. tictac4456 Group Title

brb

3. nee5277 Group Title

$5^{2}+7^{2}=x^{2} under that is, 25+49=x^{2}, below that is \sqrt{79}=\sqrt{x}^{^{2}} what does x^{2}=?$ & thanks ^.^

4. nee5277 Group Title

I wish I could show a pic, it's Pythagonean and Theorem.

5. hartnn Group Title

you want to learn pythagoras theorem or u want to know how $$x=\sqrt{79}$$ ??

6. hartnn Group Title

and x^2 = 25+49 = 74

7. hartnn Group Title

not 79

8. nee5277 Group Title

Sorry I meant 74, but I wanted to know the answer to it because there are 4 answers, 1)6.3 2)7.1 3)14.1 & 4)17.1

9. hartnn Group Title

then u need to post the entire question clearly....

10. hartnn Group Title

because sqrt 74 = 8.6

11. nee5277 Group Title

The end of the dog's leash is attached to the top of a 5-foot-tall fence post, as shown in the diagram below (this is where the equation is) The dog is 7 feet away from the base of the fence post.

12. hartnn Group Title

|dw:1356724058436:dw| whats need to be found ?

13. hartnn Group Title

if x is to be found, its 8.6

14. nee5277 Group Title

Okay thanks, how about the legs of an isosceles right triangle each measure 10 inches. WHat is the length of the hypothesis of this triangle, to the nearest tenth of an inch?

15. hartnn Group Title

again pythagoras theorem |dw:1356724579218:dw|

16. nee5277 Group Title

Answers are 6.3,7.1,14.1, and 17.1 Would it be 14.1?

17. hartnn Group Title

yes :) did u understand how ?

18. nee5277 Group Title

Lol no honestly, I need help, it was just a lucky guess for me because I knew the answer had to have a four in it right?

19. hartnn Group Title

For any right angled triangle, |dw:1356724844491:dw|

20. hartnn Group Title

did u get that ?

21. hartnn Group Title

u had a=b=10 $$c^2=10^2+10^2=200 \\ c=\sqrt{200}=14.1$$

22. hartnn Group Title

which part u have doubt with ??

23. nee5277 Group Title

Oh okay I see now thanks :) What is the value of x? $13x-2(x+4)=8x+1$

24. nee5277 Group Title

25. nee5277 Group Title

Then add 2x to both sides? 2x+2x, 2x+8x

26. hartnn Group Title

-2(4)=-8 and not +8

27. nee5277 Group Title

I'm lost at this part 11x-2x+8=8x+1 +2x +2x 11x+8=10x+1 -10x -10x?

28. hartnn Group Title

sorry, got disconnected $$13x-2(x+4)=8x+1 \\ 13x-2x\large \color{red}{+8}=8x+1 \\11x+8=8x+1 \\ 11x-8x =1-7 \\ 3x=-6 \\x=....?$$ ask if there is any doubt in any step...

29. nee5277 Group Title

I get it so the answer would be 2?

30. nee5277 Group Title

If 3(x+2)-2(x+1)=8 the value of x is? I need help pls.

31. hartnn Group Title

sorry, i did the same mistake again $$13x-2(x+4)=8x+1 \\ 13x-2x\large \color{red}{-8}=8x+1 \\11x-8=8x+1 \\ 11x-8x =1+8 \\ 3x=9 \\x=3$$

32. nee5277 Group Title

It's okay :)

33. nee5277 Group Title

would be 4 right?

34. hartnn Group Title

3(x+2)-2(x+1)=8 3x+6-2x-2=8 x+4=4 x=4 yes :)

35. hartnn Group Title

*x+4=8

36. nee5277 Group Title

Wait for that last one wouldn't it be 2 because 3 goes into 6 twice?

37. Nimi404 Group Title

Pls solve this someone has a container with 4200 millilitre of waters are in someone's container

38. hartnn Group Title

sorry, i didn't get your doubt ? 3x=9 so, x=3

39. nee5277 Group Title

Oh oh I see sorry lol it looked like a 6 for a minute. thanks. How about Debbie solved a linear equation 3(x+4)-2=16 where did she make an error? Line 1: 3(x+4)-2=16 Line 2: 3(x+4)=18 Line 3: 3x+4=18 Line 4: 3x=14 Line 5: $4\frac{ 2}{ 3 }$

40. nee5277 Group Title

Oops sorry Line 5 is suppose to say x= then what I put.

41. hartnn Group Title

3(x+4)=18 x+4 = 18/3 =6

42. hartnn Group Title

so, mistake in line 3, while distributing.

43. hartnn Group Title

if more Q coming up, then close this and ask it in a new post...

44. nee5277 Group Title

Okay thanks.

45. hartnn Group Title

welcome ^_^