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mahserindortatlisi

  • 3 years ago

Show that the function f(x) = x4 + 3x + 1 has exactly one zero on the interval [−2,−1].

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  1. abb0t
    • 3 years ago
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    Take the derivative.

  2. Yahoo!
    • 3 years ago
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    MVT

  3. mahserindortatlisi
    • 3 years ago
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    afterthat what can we proof is there a 0 point between domain

  4. mahserindortatlisi
    • 3 years ago
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    how can sorry

  5. mahserindortatlisi
    • 3 years ago
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    can you explain the solution by writing step by step? :) it's urgent :(

  6. cwrw238
    • 3 years ago
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    derivative is 4x^3 + 3 4x^3 + 3 < 0 for negative gradient x^3 < -3/4 x < (-3/4)^(1/3) = approx -0.9 this is greater than -1 so the graph is decreasing over the period -2,-1 find value of function atx = -2 and -1 f(-2) = (-2)^4 + 3(-2) + 1 = 11 f(-1) = -2 meaning it has crossed the x-axis at most once over the period

  7. mahserindortatlisi
    • 3 years ago
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    thank u for solution crw238 :)

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