Kris5
Please help...Find the sum of the first six terms of the series: 96,144,216,324,...



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mathmate
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The rule is \( a_{n+1} = 1.5 a_n \)
with \( a_0=96 , and r=1.5 \)
The partial sum is \( a_0\frac{1r^n}{1r}=(96)\frac{1(1.5)^6}{1(1.5)} \)

Kris5
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oohh okay thank you

Kris5
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:]

mathmate
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yw!