anonymous
  • anonymous
Which of the following inequalities matches the graph? (see attached photo) A y _>_3x - 5 B y < 3x - 5 C y < 1/3x - 5 D The correct inequality is not listed.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Alright, so lets pick up where we left off. Can you find two points on the line?
anonymous
  • anonymous
(4,7)

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anonymous
  • anonymous
Yup, that's one, good job.
anonymous
  • anonymous
@ilovenyc Can you find another one?
anonymous
  • anonymous
(2,8)
anonymous
  • anonymous
@ilovenyc Well, go over to 2 on the x axis, and then go up until you hit the line. What y are you at? That's how you get a point.
anonymous
  • anonymous
(2,0)?
anonymous
  • anonymous
@ilovenyc Not quite, although the drawing isn't too great. (2,1) is on the line.
anonymous
  • anonymous
Do you see how that works?
anonymous
  • anonymous
YES
anonymous
  • anonymous
Great! So now, do you remember how to find the slope?
anonymous
  • anonymous
To find the slope m of the line segment joining the points, use the slope formula
anonymous
  • anonymous
Right, so try doing that with (2,1) and (4,7)
anonymous
  • anonymous
@ilovenyc Making any progress, or do you need some help?
anonymous
  • anonymous
need some help do i add those both together?
anonymous
  • anonymous
Not quite, it's more of a subtraction. Here's the slope formula: \[\frac{y_2-y_1}{x_2-x_1} \; \; \; x_1 = 2 \; \; \; x_2 = 4 \; \; \; y_1=1 \; \; \; y_2=7 \]
anonymous
  • anonymous
@ilovenyc So see if you can use that to find the slope. I'll be back in just a little bit.
anonymous
  • anonymous
@srossd so i need to subtract that
anonymous
  • anonymous
@ilovenyc Just use that formula I wrote, plug in the numbers. And now I'll be back in a little bit :).
anonymous
  • anonymous
is the answer 13?
anonymous
  • anonymous
No, here's another hint: \[\frac{7-1}{4-2}\]
anonymous
  • anonymous
And ok, now I'm actually leaving for a little bit.
anonymous
  • anonymous
Just a few minutes, though.
anonymous
  • anonymous
@ilovenyc Alright, I'm back now. So did you get the slope from that?
anonymous
  • anonymous
6,and 2
anonymous
  • anonymous
Well, 6 divided by 2.
anonymous
  • anonymous
So the slope ends up being 3.
anonymous
  • anonymous
@ilovenyc So now you know that the line will be y=3x+b. So plug in x = 0 to that, and you'll be y=b. So look at the graph, and go to the point where x=0. Find what y is.
anonymous
  • anonymous
|dw:1356749491751:dw|
anonymous
  • anonymous
-4?
anonymous
  • anonymous
The drawing is bad again, it's actually -5. But close enough that I'm pretty sure you get it.
anonymous
  • anonymous
So if your equation was y=3x+b, and b=-5, what's your final equation?
anonymous
  • anonymous
2 = 3*(-4) + b?
anonymous
  • anonymous
No, no - just plug in the value of b (-5) to y=3x+b. The x and y should stay.
anonymous
  • anonymous
okay
anonymous
  • anonymous
@ilovenyc Do you understand, or do you need some help?
anonymous
  • anonymous
need some help
anonymous
  • anonymous
Ok, so you solved for b, so just put it where b was. The equation comes out to be y=3x-5.
anonymous
  • anonymous
Do you see how that works, plugging in -5 for b?
anonymous
  • anonymous
so B is the answer
anonymous
  • anonymous
Actually, it's A, since everything above the line is shaded. B would be the opposite shading.
anonymous
  • anonymous
oh okay
anonymous
  • anonymous
But still, good job!
anonymous
  • anonymous
And again, sorry for elongating this so much - I just wanted to make sure you understand how to do it.
anonymous
  • anonymous
@ilovenyc So do you feel like you have a good grasp on how to do this type of problem now?
anonymous
  • anonymous
@srossd i think so...
anonymous
  • anonymous
Alright, good. I can make up another one for you to try if you want.
anonymous
  • anonymous
well i have more problems that i need to do on my homework
anonymous
  • anonymous
Oh, ok. Need help with those?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Ok, want to post a new problem?
anonymous
  • anonymous
@ilovenyc I'll be on the lookout for a new post.

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