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How to find the thevenin for c-d terminal ?

I mean, thevenin voltage :)

|dw:1356752136345:dw| open the current source and short the voltage source you will get Rth

I did, but I didn't get the right answer :(

hold on let me solve

I got 2.667 – j4 Ω for Rth, n the answer for Vth is 9.614∠56.31° V

did you convert 2.667 -j4 into polar form , you've got right answer

i think you should be using superposition principle

ehh ehh, isn't it suppose to be supermesh ? D: there's current source within the loop

ouhh, okayy, but the concept Im using just now is right right ?

yep, its right i am sure you'll get your thevnin voltage by that

well, Vth, you can use voltage division rule

hold on, currently using superposition to solve it :)

|dw:1356753391535:dw| calculate voltage drop at point a and b

|dw:1356753632924:dw|

oh, some text missing ><

can I just ignore the terminal 1st, n solve it like a normal question ?

you dont need to go through all that stuff , just use superposition and you are done

D: u can guess the answer just by watching it ? awesome ! D:

|dw:1356762940423:dw| look here these are V1 and V2

yeap2, but then ... v1 isn't connected with v2 D: