Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

feezul_93

  • one year ago

Complex number in circuit

  • This Question is Closed
  1. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    How to find the thevenin for c-d terminal ?

    1 Attachment
  2. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I mean, thevenin voltage :)

  3. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1356752136345:dw| open the current source and short the voltage source you will get Rth

  4. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I did, but I didn't get the right answer :(

  5. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    hold on let me solve

  6. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I got 2.667 – j4 Ω for Rth, n the answer for Vth is 9.614∠56.31° V

  7. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    did you convert 2.667 -j4 into polar form , you've got right answer

  8. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i got the Rth, but Vth ... I get it wrong :( wondering where's my mistake, Im using mesh analysis to find current flowing through capacitor, n times the capacitor to get Vth ... am I wrong ?

  9. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i think you should be using superposition principle

  10. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ehh ehh, isn't it suppose to be supermesh ? D: there's current source within the loop

  11. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    there will be nothing messy , give a try by that first eliminate current source and then eliminate voltage one

  12. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ouhh, okayy, but the concept Im using just now is right right ?

  13. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yep, its right i am sure you'll get your thevnin voltage by that

  14. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    but I didn't T^T nevermind, i try to use superposition now, thanks :) btw, did u get the Vth ? cause I got the feeling that the answer given is wrong, hahaha

  15. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    well, Vth, you can use voltage division rule

  16. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    hold on, currently using superposition to solve it :)

  17. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1356753391535:dw| calculate voltage drop at point a and b

  18. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1356753632924:dw|

  19. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh, some text missing ><

  20. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    actually you are supposed to calculate thevenin voltage across the capacitor that is i guess your load here, so you have to make it open terminal to calculate the voltage drop at load

  21. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah yeahh, that's exactly what I did just now ... n base on your drawing ... we're using nodal analysis ? cause I prefer to find current through capacitor n simply times it, but I don't really know if my concept is right ... there are too many ways to solve this @.@

  22. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    can I just ignore the terminal 1st, n solve it like a normal question ?

  23. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you dont need to go through all that stuff , just use superposition and you are done

  24. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    T^T, i get the same answer like my previous method ... I guess the answer given is wrong ... but still ... I can't clarify it if Im the only 1 who get this answer ... did you get the same answer as given ?

  25. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    actually i hate these complex calculation lol so i can write the method you can match it , that is voltage drop due to 20 V source and due to current source

  26. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i'll upload the solution and if you are getting same answer then i guess your book has got some mistake, i am not sure but i guess its 4 angle 56 V

  27. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    hahahahaha, yeaappp, same goes to me, and I wonder who create this stuff, what kind of brain he had -___- but i guess i understand the flow of answering this kind of question, ouhh really ? thanks a lot :)

  28. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    D: u can guess the answer just by watching it ? awesome ! D:

  29. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you are welcome :D and yes the answer is around what i said, but i have to check it again , only reason is i hate this complex calculation lol i'll have to use calculator , dont worry i'll do it :D :)

  30. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I don't get it, why we do we have to let V1 - V2 ...

  31. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we are finding V1-V2 because just take off the capacitor and you are supposed to find the terminal voltage

  32. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    soo, deducting v2 by v1 is equal too ... V at terminal ? D: I don't see relation between it, can't even imagine it -_-"

  33. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1356762940423:dw| look here these are V1 and V2

  34. feezul_93
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yeap2, but then ... v1 isn't connected with v2 D:

  35. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    when we measure potential difference we measure the potential difference at two terminals, that is why we have eliminated capacitor it is not needed to be connected to measure the potential drop across those terminals

  36. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if like you will join that two points by wire there will be zero potential difference which means both the points at same potential or short circuit

  37. ghazi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    just think of using multimeter for the measurement of potential difference across a resistor or any element , we place two terminals of multimeter at the two ends

  38. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.