anonymous
  • anonymous
integrate:(x+3)/sqrt(x^2+4x+5)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
I would try to factor the quadratic or something.
anonymous
  • anonymous
u have to firs express numerator as A(diif of denom )+B where A and B are constatnts to be dtermined thus A(2x+4) +B =x+3
anonymous
  • anonymous
After you factor the denominator you will get an expression that lends itself (not too nicely) to a few layers of substitution. I am getting a rather complicated trigonometric answer when I do it.

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anonymous
  • anonymous
equating coefficient on both sides we have 2A=1 or A=1/2 and 4A+B=3 or B=1 thus (x+3)= 1/2 (2x+4) +1 hence reqd integ breaks down to two as 1/2 (2x+4)/(x^2+4x+5) +1 /((x^2+4x+5) let I =integral of 1/2 (2x+4)/(x^2+4x+5) and J = integral of 1 /((x^2+4x+5) now one has to eavaluate first I and J
anonymous
  • anonymous
Actually looks like you have to complete the square of the denominator.
anonymous
  • anonymous
Right, after completing the square on the bottom you can obtain an equivalent form where u = x + 2: integrate (u + 1) / sqrt(u^2 + 1) du Still complicated from here though.
anonymous
  • anonymous
\[(a+b)^2 = a^2 +2ab + b^2 \\ a = x \\ b = ? \]
anonymous
  • anonymous
for I substitute (x^2+4x+5)=z or (2x+4)dx=dz hence I =1/2 (inegral of dz/z) =1/2 lnz +c1 or I=1/2 ln (x^2+4x+5)+c1
anonymous
  • anonymous
Now for J one has to complete sqaures thus (x^2+4x+5)=(x^2+4x+4+1)=(x+2)^2 +1
anonymous
  • anonymous
@drake_96 You there?
anonymous
  • anonymous
J= integral of 1/((x+2)^2 +1) = tan^-1(x+2) +c2
anonymous
  • anonymous
thus reqd answer is 1/2 ln (x^2+4x+5) + tan^-1(x+2) +c [ where c=c1+c2 all integrating constant]
anonymous
  • anonymous
I think the derivative of the function you provided yields (x + 3) / (x^2 + 4x + 5) instead of (x + 3) / sqrt(x^2 + 4x + 5). I got sqrt(x^2 + 4x + 5) + ln (x + 2 + sqrt( (x + 2)^2 + 1)) for the final answer. Can you double check this?
anonymous
  • anonymous
@LogicalApple :you are right.

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