Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

BelleFlower

Please wait for image! Logarithms question

  • one year ago
  • one year ago

  • This Question is Closed
  1. BelleFlower
    Best Response
    You've already chosen the best response.
    Medals 0

    • one year ago
    1 Attachment
  2. BelleFlower
    Best Response
    You've already chosen the best response.
    Medals 0

    Question 11! :)

    • one year ago
  3. A.Avinash_Goutham
    Best Response
    You've already chosen the best response.
    Medals 0

    loga - logb = log(a/b) loga + logb = log(a*b) x=log(e^x) logx=logy => x=y now help urself

    • one year ago
  4. LogicalApple
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1356767087691:dw| Can you think of the next step?

    • one year ago
  5. LogicalApple
    Best Response
    You've already chosen the best response.
    Medals 1

    (That thing in the denominator of the parentheses is a 'b' -- sorry for sloppy artwork)

    • one year ago
  6. BelleFlower
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm still not sure how to continue actually... :/ @LogicalApple

    • one year ago
  7. LogicalApple
    Best Response
    You've already chosen the best response.
    Medals 1

    Consider e and ln as inverse functions. I.e., ln(e^x) = x, and e^(ln(x)) = x. Try raising e to the power of both sides. For example, on the left side you would get e^(ln K) = K

    • one year ago
  8. LogicalApple
    Best Response
    You've already chosen the best response.
    Medals 1

    And whatever you do to one side you have to do to the other

    • one year ago
  9. BelleFlower
    Best Response
    You've already chosen the best response.
    Medals 0

    What are inverse functions? Sorry i don't really get it

    • one year ago
  10. LogicalApple
    Best Response
    You've already chosen the best response.
    Medals 1

    An inverse function cancels out the original function. Like square and square root functions are inverses of each other. Multiplication and division are inverses. Here, e and ln are inverses. That is why when we have e^(ln K), the e and ln cancel leaving only K.

    • one year ago
  11. BelleFlower
    Best Response
    You've already chosen the best response.
    Medals 0

    But I am supposed to solve this just using the power, product, quotient laws and the change-of-base law....

    • one year ago
  12. LogicalApple
    Best Response
    You've already chosen the best response.
    Medals 1

    But I see there is an 'e' in the answer, so you must be able to use the function.

    • one year ago
  13. LogicalApple
    Best Response
    You've already chosen the best response.
    Medals 1

    I will present a solution. Tell me if you have any questions about it. One sec.

    • one year ago
  14. LogicalApple
    Best Response
    You've already chosen the best response.
    Medals 1

    • one year ago
    1 Attachment
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.