anonymous
  • anonymous
divisor=3 cand=3 count=2 while(count<1000): if cand%divisor==0: if cand==divisor: cand=cand+2 divisor=3 count=count+1 print 'inside_if_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor) else: cand=cand+2 divisor=3 print 'inside_else_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor) else: divisor=divisor+1 print 'outside_else_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor) prin
MIT 6.00 Intro Computer Science (OCW)
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I feel like i'm close to getting PS1, but once my counter hits 999, it hits the first inside_if_statement again and thus adds 2 to the 1000th prime. I'm not sure of a way around this... Would someone mind taking a look?
MicroBot
  • MicroBot
what is the last print statement? i think there is some of your code missing.
anonymous
  • anonymous
my final print statement basically says "print cand"

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anonymous
  • anonymous
figured it out--here's the working version: divisor=3 cand=3 count=2 while(count<1001): if cand%divisor==0: if cand==divisor: cand=cand+2 divisor=3 count=count+1 ##print 'inside_if_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor) if count==1001: cand=cand-2 else: cand=cand-1+1 else: cand=cand+2 divisor=3 ##print 'inside_else_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor) else: divisor=divisor+1 ##print 'outside_else_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor) print cand
MicroBot
  • MicroBot
im glad i could help :P xD now seriously : gj for figuring it out!:)and im sry i couldnt help cause i had no time:P maybe next time !

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