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DLS

  • 2 years ago

find theta!

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  1. DLS
    • 2 years ago
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    \[\LARGE \sqrt{3}\sin \theta-\cos \theta=2\]

  2. hartnn
    • 2 years ago
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    \(\LARGE (\sqrt{3}/2)\sin \theta-(1/2)\cos \theta=2/2 \)

  3. DLS
    • 2 years ago
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    you're the man!

  4. hartnn
    • 2 years ago
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    now write cos a = \sqrt 3/2 ,sin a =1/2

  5. hartnn
    • 2 years ago
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    where a=...?

  6. DLS
    • 2 years ago
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    60

  7. DLS
    • 2 years ago
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    pi/3

  8. hartnn
    • 2 years ago
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    no.

  9. DLS
    • 2 years ago
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    oh sorry!!

  10. DLS
    • 2 years ago
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    pi/6

  11. hartnn
    • 2 years ago
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    sin ... = 1/2 ?

  12. hartnn
    • 2 years ago
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    yes.

  13. UsukiDoll
    • 2 years ago
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    30 degrees

  14. hartnn
    • 2 years ago
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    what is \(cos 30sin \theta-sin30 cos \theta=..?\)

  15. DLS
    • 2 years ago
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    i messed up u,u

  16. DLS
    • 2 years ago
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    sin(A-B)

  17. UsukiDoll
    • 2 years ago
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    |dw:1356774577698:dw|

  18. hartnn
    • 2 years ago
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    sin [\(\theta\)-30] = 1 = sin 90

  19. hartnn
    • 2 years ago
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    got that ^ ?

  20. DLS
    • 2 years ago
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    i didnt get that diag! but yes what u said

  21. DLS
    • 2 years ago
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    okay got the diag too

  22. hartnn
    • 2 years ago
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    so, theta =... ?

  23. UsukiDoll
    • 2 years ago
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    I was drawing the triangle with its values 0_0

  24. DLS
    • 2 years ago
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    pi/2 right?what else :/

  25. UsukiDoll
    • 2 years ago
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    |dw:1356774667353:dw|

  26. hartnn
    • 2 years ago
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    that means , you didn't get this... sin [θ-30] = 1 = sin 90

  27. DLS
    • 2 years ago
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    im getting embarassed with so many people viewing this ques lloll

  28. LogicalApple
    • 2 years ago
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    We are all curious!

  29. hba
    • 2 years ago
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    Interesting question :P

  30. hartnn
    • 2 years ago
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    dls, write the step till how much u understood totally.

  31. DLS
    • 2 years ago
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    okay

  32. DLS
    • 2 years ago
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    why did we interchange the values cos a = \sqrt 3/2 ,sin a =1/2? we had sin with sqrt 3/2 and cos with 1/2

  33. hartnn
    • 2 years ago
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    when did we have sin with sqrt 3/2 ?? and you can take that also, then u have to use a different formula.

  34. DLS
    • 2 years ago
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    ur first post O_O

  35. hartnn
    • 2 years ago
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    \(\LARGE (\sqrt{3}/2)\sin \theta-(1/2)\cos \theta=2/2\) \(\LARGE \cos 30\sin \theta-\sin 30\cos \theta=1\) \(\sin(\theta-30)=sin 90 \\ \theta =...?\)

  36. DLS
    • 2 years ago
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    120?

  37. hartnn
    • 2 years ago
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    yes, u got it ?

  38. DLS
    • 2 years ago
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    yes..much better when u wrote that together !! and we had less people lol

  39. DLS
    • 2 years ago
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    we have only ONE possible value?

  40. DLS
    • 2 years ago
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    okay thats obv..thanks! and thanks to the spectators >>

  41. hartnn
    • 2 years ago
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    u want general expression ?

  42. DLS
    • 2 years ago
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    sure

  43. DLS
    • 2 years ago
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    but thats not reqd.i just wanted to know the possible values of theta from 0 to 2pi

  44. hartnn
    • 2 years ago
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    then only 120

  45. DLS
    • 2 years ago
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    yes..thats it!thanks!

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