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@hartnn help? lol
u said that was last Question! lol :"P
i was just kidding....
lol i know sorry but then i just wanted to get this outta the way. I only have 4 questions this time i promise
If x measures time (in years) then the value of y this year is 0.35·2.3^x, and next year it's 0.35·2.3^(x+1) so, can u calculate annual increase from this ?
Please, please please just give me a letter? I beg you!
sorry, that i cannot. its against CoC here.
u just subtract 0.35·2.3^x from 0.35·2.3^(x+1)
its not difficult really.....
is that a x sign in between 0.35 and the 2.3^x ?
and i believe the Question is \(y=0.35 (0.23)^x\) right ? and yes.
\(\% increase=(final-initial)*100/initial \) here, initial is =0.35·2.3^x final =0.35·2.3^(x+1)
just plug in values, and u get the answer easily.
i got it thanks. sorry i got that one an then just started doing the other ones. thank you
what u got it as ?
so that i can verify..
130% is correct in this instance. Consider the percent increase from 0.35(2.3)^1 to 0.35(2.3)^2
yes, its correct
For growth functions, the easiest way to determine the growth rate is to consider it of the form: y = a(1 + r)^x, where r is the percent increase