anonymous
  • anonymous
Find the annual percent increase or decrease that y = 0.35(2.3)x models. (1 point) A.230% increase B.130% increase C.30% decrease D.65% decrease
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
@hartnn help? lol
hartnn
  • hartnn
u said that was last Question! lol :"P
hartnn
  • hartnn
i was just kidding....

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anonymous
  • anonymous
lol i know sorry but then i just wanted to get this outta the way. I only have 4 questions this time i promise
hartnn
  • hartnn
If x measures time (in years) then the value of y this year is 0.35·2.3^x, and next year it's 0.35·2.3^(x+1) so, can u calculate annual increase from this ?
anonymous
  • anonymous
Please, please please just give me a letter? I beg you!
hartnn
  • hartnn
sorry, that i cannot. its against CoC here.
hartnn
  • hartnn
u just subtract 0.35·2.3^x from 0.35·2.3^(x+1)
anonymous
  • anonymous
-_-
hartnn
  • hartnn
its not difficult really.....
anonymous
  • anonymous
is that a x sign in between 0.35 and the 2.3^x ?
hartnn
  • hartnn
and i believe the Question is \(y=0.35 (0.23)^x\) right ? and yes.
hartnn
  • hartnn
\(\% increase=(final-initial)*100/initial \) here, initial is =0.35·2.3^x final =0.35·2.3^(x+1)
hartnn
  • hartnn
just plug in values, and u get the answer easily.
anonymous
  • anonymous
i got it thanks. sorry i got that one an then just started doing the other ones. thank you
hartnn
  • hartnn
what u got it as ?
hartnn
  • hartnn
so that i can verify..
anonymous
  • anonymous
130
anonymous
  • anonymous
b
anonymous
  • anonymous
130% is correct in this instance. Consider the percent increase from 0.35(2.3)^1 to 0.35(2.3)^2
hartnn
  • hartnn
yes, its correct
anonymous
  • anonymous
For growth functions, the easiest way to determine the growth rate is to consider it of the form: y = a(1 + r)^x, where r is the percent increase

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