Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Find the annual percent increase or decrease that y = 0.35(2.3)x models. (1 point) A.230% increase B.130% increase C.30% decrease D.65% decrease

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
@hartnn help? lol
u said that was last Question! lol :"P
i was just kidding....

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

lol i know sorry but then i just wanted to get this outta the way. I only have 4 questions this time i promise
If x measures time (in years) then the value of y this year is 0.35·2.3^x, and next year it's 0.35·2.3^(x+1) so, can u calculate annual increase from this ?
Please, please please just give me a letter? I beg you!
sorry, that i cannot. its against CoC here.
u just subtract 0.35·2.3^x from 0.35·2.3^(x+1)
-_-
its not difficult really.....
is that a x sign in between 0.35 and the 2.3^x ?
and i believe the Question is \(y=0.35 (0.23)^x\) right ? and yes.
\(\% increase=(final-initial)*100/initial \) here, initial is =0.35·2.3^x final =0.35·2.3^(x+1)
just plug in values, and u get the answer easily.
i got it thanks. sorry i got that one an then just started doing the other ones. thank you
what u got it as ?
so that i can verify..
130
b
130% is correct in this instance. Consider the percent increase from 0.35(2.3)^1 to 0.35(2.3)^2
yes, its correct
For growth functions, the easiest way to determine the growth rate is to consider it of the form: y = a(1 + r)^x, where r is the percent increase

Not the answer you are looking for?

Search for more explanations.

Ask your own question