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u said that was last Question!
lol :"P

i was just kidding....

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Please, please please just give me a letter? I beg you!

sorry, that i cannot.
its against CoC here.

u just subtract 0.35·2.3^x from 0.35·2.3^(x+1)

-_-

its not difficult really.....

is that a x sign in between 0.35 and the 2.3^x ?

and i believe the Question is \(y=0.35 (0.23)^x\)
right ?
and yes.

\(\% increase=(final-initial)*100/initial \)
here, initial is =0.35·2.3^x
final =0.35·2.3^(x+1)

just plug in values, and u get the answer easily.

i got it thanks. sorry i got that one an then just started doing the other ones. thank you

what u got it as ?

so that i can verify..

130

130% is correct in this instance. Consider the percent increase from 0.35(2.3)^1 to 0.35(2.3)^2

yes, its correct

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