A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

suss
 one year ago
Best ResponseYou've already chosen the best response.0it was supposed to x to the power logylogz y to the power logzlogx z to the power logxlogy

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\huge x^{\log y\log z}y^{\log z\log x}z^{\log x\log y}\) like this ?

suss
 one year ago
Best ResponseYou've already chosen the best response.0ah thank god..yes like that

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1consider \(\huge \log[x^{\log y\log z}y^{\log z\log x}z^{\log x\log y}]\) can u simplify that ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1use, \(\log AB=\log A+\log B \\ \log A^{B}=B\log A\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1you should get that =0 = ln 1

suss
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand y u multiplied the whole by log????

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1else, nothing can't be really done to that expression

suss
 one year ago
Best ResponseYou've already chosen the best response.0i have done that problem in this way \[x ^{\log y/z}y ^{\log z/x}z ^{\log x/y}\]

suss
 one year ago
Best ResponseYou've already chosen the best response.0and i cudnt figure out the next step..... :(

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i know, i tried that also....since i could not proceed, i thought of taking log....

suss
 one year ago
Best ResponseYou've already chosen the best response.0if u dont mind,can u show me the simplification process...??? :)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\huge \log[x^{\log y\log z}y^{\log z\log x}z^{\log x\log y}] \\\large =\log[x^{\log y\log z}]+\log[y^{\log z\log x}]+\log[z^{\log x\log y}]\) got this ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1now use \( \\ \log A^{B}=B\log A\)

suss
 one year ago
Best ResponseYou've already chosen the best response.0oh sorry man i jus lost connection leeme check it out

suss
 one year ago
Best ResponseYou've already chosen the best response.0y did u keep the + sign ???

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1because \(\log AB=\log A+\log B \\ \)

suss
 one year ago
Best ResponseYou've already chosen the best response.0ah finally got it .....thx a ton man

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1sure ? u getting that = 0 ? then write 0=log 1

suss
 one year ago
Best ResponseYou've already chosen the best response.0yes 100%..i hav to use formula of log ab bak ther ......i really got it man
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.