A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Xlogylogz.ylogzlogx.zlogxlogy=1
how to prove this??
anonymous
 3 years ago
Xlogylogz.ylogzlogx.zlogxlogy=1 how to prove this??

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it was supposed to x to the power logylogz y to the power logzlogx z to the power logxlogy

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\huge x^{\log y\log z}y^{\log z\log x}z^{\log x\log y}\) like this ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ah thank god..yes like that

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1consider \(\huge \log[x^{\log y\log z}y^{\log z\log x}z^{\log x\log y}]\) can u simplify that ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1use, \(\log AB=\log A+\log B \\ \log A^{B}=B\log A\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1you should get that =0 = ln 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont understand y u multiplied the whole by log????

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1else, nothing can't be really done to that expression

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i have done that problem in this way \[x ^{\log y/z}y ^{\log z/x}z ^{\log x/y}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and i cudnt figure out the next step..... :(

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1i know, i tried that also....since i could not proceed, i thought of taking log....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if u dont mind,can u show me the simplification process...??? :)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\huge \log[x^{\log y\log z}y^{\log z\log x}z^{\log x\log y}] \\\large =\log[x^{\log y\log z}]+\log[y^{\log z\log x}]+\log[z^{\log x\log y}]\) got this ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1now use \( \\ \log A^{B}=B\log A\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh sorry man i jus lost connection leeme check it out

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y did u keep the + sign ???

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1because \(\log AB=\log A+\log B \\ \)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ah finally got it .....thx a ton man

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1sure ? u getting that = 0 ? then write 0=log 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes 100%..i hav to use formula of log ab bak ther ......i really got it man
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.