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|dw:1356781451262:dw|

brb

May I know what (x2, y2) is??

x_2, y_2 are the coordinates of C

probably you would end up with two sets of point, choose the the point where y>0

Algebra matters.

C = (0, 2)

yes!! sorry i was careless ... did you find out answer?

\(x^2 + y^2 +6x - 2y =0\) ---(1)
\(x^2+(y-2)^2 =20\) => \(x^2 + y^2 -4y+4 =20\) ---(2)

he?

Do you mean I knew the answer?

co-ordinates of A can also be found similarly.

A = (-6, 0)

D = (4, 0)

then u know equation of line BD
can't u use that to find co-ordinates of B ?

solving equation of line and circle simultaneously.

are u sure about D =(4,0)??

oh, i somehow got 36 instead of 40, thats why i was stuck.....

Correction: o.O Did I make a mistake? :S

no, u are correct.

Okay, thanks again! I didn't thought of the line. I'm just too stupid :(

happens!
i just did a silly mistake of 6*4 =20 :P

did anyone notice :
|dw:1356789155290:dw|

how do we know slope of OB?

ohh..

as we know slope of OC

yep..exactly..

given slope of OB and O, we can find B, no need of any distance..

Not so relevant.
|dw:1356789503661:dw|

ohh yes!!
COA are collinear !

how does that make it any simpler ?

i dont know,,just a good fact to know! :D

''Not so relevant.'' :P

:P
ok ..

u got 2 more easy methods ;)

Yes! Yes! Thanks! Thanks!!