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 2 years ago
An interesting question! :D
ABC is an equilateral triangle such that the vertices B and C lie on two parallel line at a distance of 6.If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is=?
 2 years ago
An interesting question! :D ABC is an equilateral triangle such that the vertices B and C lie on two parallel line at a distance of 6.If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is=?

This Question is Closed

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1if B and C lie on parallel lines, then BC = side = 6 ...?

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0no unit mentioned if u are asking for one

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1i was not asking, i was telling side =6

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1356782149154:dw my diagram

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1if ABC is equilateral AB=BC=AC=6

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1356782275365:dw so cant we do like this.. sin60=h/4

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1u wanted to know length of side ... = BC = 6 thats it.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1maybe the side BC is tilted , then

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1so, your figure is incorrect.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1where u have shown BC =6

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1356782465079:dw

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0then wdw:1356783287510:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(a=\sqrt{x^24^2} \\ b=\sqrt{x^26^2} \\ a+b=\sqrt{x^22^2}\) you can find 'x' from here.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1i hope ther's a shorter way...

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0solution and answer given in my book is DANGEROUS :/

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=sqrt%28x%5E216%29%2Bsqrt%28x%5E236%29%3Dsqrt%28x%5E24%29 what answer u have ?

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0I have.. \[\LARGE 2 \frac{\sqrt{28}}{\sqrt{3}}\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1which is exactly what i got.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\LARGE 2 \frac{\sqrt{28}}{\sqrt{3}}=\LARGE 4\frac{\sqrt{7}}{\sqrt{3}}\)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1using \(a=\sqrt{x^24^2} \\ b=\sqrt{x^26^2} \\ a+b=\sqrt{x^22^2}\)

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0hold on one sec..let me go through it once again

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0lol that was a nice method :

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1just pythagoras, thrice...
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