DLS
An interesting question! :D
ABC is an equilateral triangle such that the vertices B and C lie on two parallel line at a distance of 6.If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is=?
Delete
Share
This Question is Closed
hartnn
Best Response
You've already chosen the best response.
1
if B and C lie on parallel lines, then BC = side = 6 ...?
DLS
Best Response
You've already chosen the best response.
0
units
DLS
Best Response
You've already chosen the best response.
0
no unit mentioned if u are asking for one
hartnn
Best Response
You've already chosen the best response.
1
i was not asking, i was telling side =6
DLS
Best Response
You've already chosen the best response.
0
oh :P
DLS
Best Response
You've already chosen the best response.
0
|dw:1356782149154:dw|
my diagram
hartnn
Best Response
You've already chosen the best response.
1
if ABC is equilateral
AB=BC=AC=6
DLS
Best Response
You've already chosen the best response.
0
|dw:1356782275365:dw|
so cant we do like this..
sin60=h/4
hartnn
Best Response
You've already chosen the best response.
1
u wanted to know length of side ... = BC = 6
thats it.
DLS
Best Response
You've already chosen the best response.
0
O_o
answer isnt this!!
DLS
Best Response
You've already chosen the best response.
0
we have to find length
hartnn
Best Response
You've already chosen the best response.
1
of ?
DLS
Best Response
You've already chosen the best response.
0
side of the eq triangle :/
hartnn
Best Response
You've already chosen the best response.
1
maybe the side BC is tilted , then
DLS
Best Response
You've already chosen the best response.
0
yes..thats what im saying
hartnn
Best Response
You've already chosen the best response.
1
so, your figure is incorrect.
DLS
Best Response
You've already chosen the best response.
0
:/
hartnn
Best Response
You've already chosen the best response.
1
where u have shown BC =6
experimentX
Best Response
You've already chosen the best response.
0
|dw:1356782465079:dw|
DLS
Best Response
You've already chosen the best response.
0
why wont that be 60 :o
hartnn
Best Response
You've already chosen the best response.
1
|dw:1356782731705:dw|
DLS
Best Response
You've already chosen the best response.
0
thats nt touching?
hartnn
Best Response
You've already chosen the best response.
1
ofcourse, it is...
DLS
Best Response
You've already chosen the best response.
0
then w|dw:1356783287510:dw|
hartnn
Best Response
You've already chosen the best response.
1
i have a long way.
hartnn
Best Response
You've already chosen the best response.
1
|dw:1356783439425:dw|
hartnn
Best Response
You've already chosen the best response.
1
\(a=\sqrt{x^2-4^2} \\ b=\sqrt{x^2-6^2} \\ a+b=\sqrt{x^2-2^2}\)
you can find 'x' from here.
hartnn
Best Response
You've already chosen the best response.
1
i hope ther's a shorter way...
DLS
Best Response
You've already chosen the best response.
0
x=root 52 or smt?
DLS
Best Response
You've already chosen the best response.
0
solution and answer given in my book is DANGEROUS :/
DLS
Best Response
You've already chosen the best response.
0
I have..
\[\LARGE 2 \frac{\sqrt{28}}{\sqrt{3}}\]
hartnn
Best Response
You've already chosen the best response.
1
which is exactly what i got.
hartnn
Best Response
You've already chosen the best response.
1
\(\LARGE 2 \frac{\sqrt{28}}{\sqrt{3}}=\LARGE 4\frac{\sqrt{7}}{\sqrt{3}}\)
DLS
Best Response
You've already chosen the best response.
0
okay yes
hartnn
Best Response
You've already chosen the best response.
1
using
\(a=\sqrt{x^2-4^2} \\ b=\sqrt{x^2-6^2} \\ a+b=\sqrt{x^2-2^2}\)
DLS
Best Response
You've already chosen the best response.
0
hold on one sec..let me go through it once again
DLS
Best Response
You've already chosen the best response.
0
lol that was a nice method :|
hartnn
Best Response
You've already chosen the best response.
1
just pythagoras, thrice...
DLS
Best Response
You've already chosen the best response.
0
yeah..!