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hartnn
 one year ago
Best ResponseYou've already chosen the best response.2domain means the values which 'x' can take in that equation.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2do u see any values that 'x' can't take ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2(1)there is no denominator, if there was, then 'x' could not take values for which denominator=0

suss
 one year ago
Best ResponseYou've already chosen the best response.0so ther is no soln for this??

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2(2) there is no \(\sqrt.\) sign, if there was , then 'x' cannot take values for which the expression under \(\sqrt{...}\)becomes negative.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2here, none of the 2 cases (1) or (2) arise. so 'x' can take all real values.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2so, domain is ALL real numbers R

suss
 one year ago
Best ResponseYou've already chosen the best response.0sorry i quite didnt get it

suss
 one year ago
Best ResponseYou've already chosen the best response.0x belongs to R then can we supoose any no we want in the place of x??

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2yes, x can take any real value. u have options/choices ?

suss
 one year ago
Best ResponseYou've already chosen the best response.0how wud u solve this prob?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2example : f(x) =1/ x x cannot take value =0 f(x) = 1/(x3) x cannot take value = 3 f(x) = sqrt{x4} x cannot take value less than 4

suss
 one year ago
Best ResponseYou've already chosen the best response.0can u be mo` specific...?i cant understand

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2i just gave u specific examples. and there's nothing to solve, you can say 'x' can take all real values...

suss
 one year ago
Best ResponseYou've already chosen the best response.0y did u add 3 in da denominator?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0By the way, all polynomials have the domain \((\infty,\infty)\) a.k.a \(\mathbb{R}\).

suss
 one year ago
Best ResponseYou've already chosen the best response.0can u do the whole process??

BluFoot
 one year ago
Best ResponseYou've already chosen the best response.0Domain means whenever the function exists. To figure this out, just find when the function does not exist, meaning when you're dividing by 0. In this case, you're never dividing by 0, so the function ALWAYS exists, so the domain is ]inf,inf[, also know as "R" for all real numbers. If say f(x) = 1/(x4), then the domain is ]inf,4[U]4,inf[, because the function exists everywhere except at x=4.
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