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suss

  • 2 years ago

find the domain y=f(x)=x^2-6x+6

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  1. hartnn
    • 2 years ago
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    domain means the values which 'x' can take in that equation.

  2. hartnn
    • 2 years ago
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    do u see any values that 'x' can't take ?

  3. suss
    • 2 years ago
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    i dont get it......??

  4. hartnn
    • 2 years ago
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    (1)there is no denominator, if there was, then 'x' could not take values for which denominator=0

  5. suss
    • 2 years ago
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    so ther is no soln for this??

  6. hartnn
    • 2 years ago
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    (2) there is no \(\sqrt.\) sign, if there was , then 'x' cannot take values for which the expression under \(\sqrt{...}\)becomes negative.

  7. hartnn
    • 2 years ago
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    here, none of the 2 cases (1) or (2) arise. so 'x' can take all real values.

  8. hartnn
    • 2 years ago
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    so, domain is ALL real numbers R

  9. hartnn
    • 2 years ago
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    understood ?

  10. suss
    • 2 years ago
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    sorry i quite didnt get it

  11. hartnn
    • 2 years ago
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    which par ?

  12. suss
    • 2 years ago
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    x belongs to R then can we supoose any no we want in the place of x??

  13. hartnn
    • 2 years ago
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    yes, x can take any real value. u have options/choices ?

  14. suss
    • 2 years ago
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    how wud u solve this prob?

  15. hartnn
    • 2 years ago
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    example : f(x) =1/ x x cannot take value =0 f(x) = 1/(x-3) x cannot take value = 3 f(x) = sqrt{x-4} x cannot take value less than 4

  16. suss
    • 2 years ago
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    can u be mo` specific...?i cant understand

  17. hartnn
    • 2 years ago
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    i just gave u specific examples. and there's nothing to solve, you can say 'x' can take all real values...

  18. suss
    • 2 years ago
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    y did u add -3 in da denominator?

  19. ParthKohli
    • 2 years ago
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    By the way, all polynomials have the domain \((-\infty,\infty)\) a.k.a \(\mathbb{R}\).

  20. suss
    • 2 years ago
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    can u do the whole process??

  21. BluFoot
    • 2 years ago
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    Domain means whenever the function exists. To figure this out, just find when the function does not exist, meaning when you're dividing by 0. In this case, you're never dividing by 0, so the function ALWAYS exists, so the domain is ]-inf,inf[, also know as "R" for all real numbers. If say f(x) = 1/(x-4), then the domain is ]-inf,-4[U]-4,inf[, because the function exists everywhere except at x=-4.

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