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hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2domain means the values which 'x' can take in that equation.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2do u see any values that 'x' can't take ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2(1)there is no denominator, if there was, then 'x' could not take values for which denominator=0

suss
 2 years ago
Best ResponseYou've already chosen the best response.0so ther is no soln for this??

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2(2) there is no \(\sqrt.\) sign, if there was , then 'x' cannot take values for which the expression under \(\sqrt{...}\)becomes negative.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2here, none of the 2 cases (1) or (2) arise. so 'x' can take all real values.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2so, domain is ALL real numbers R

suss
 2 years ago
Best ResponseYou've already chosen the best response.0sorry i quite didnt get it

suss
 2 years ago
Best ResponseYou've already chosen the best response.0x belongs to R then can we supoose any no we want in the place of x??

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2yes, x can take any real value. u have options/choices ?

suss
 2 years ago
Best ResponseYou've already chosen the best response.0how wud u solve this prob?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2example : f(x) =1/ x x cannot take value =0 f(x) = 1/(x3) x cannot take value = 3 f(x) = sqrt{x4} x cannot take value less than 4

suss
 2 years ago
Best ResponseYou've already chosen the best response.0can u be mo` specific...?i cant understand

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i just gave u specific examples. and there's nothing to solve, you can say 'x' can take all real values...

suss
 2 years ago
Best ResponseYou've already chosen the best response.0y did u add 3 in da denominator?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0By the way, all polynomials have the domain \((\infty,\infty)\) a.k.a \(\mathbb{R}\).

suss
 2 years ago
Best ResponseYou've already chosen the best response.0can u do the whole process??

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0Domain means whenever the function exists. To figure this out, just find when the function does not exist, meaning when you're dividing by 0. In this case, you're never dividing by 0, so the function ALWAYS exists, so the domain is ]inf,inf[, also know as "R" for all real numbers. If say f(x) = 1/(x4), then the domain is ]inf,4[U]4,inf[, because the function exists everywhere except at x=4.
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