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hartnn Group TitleBest ResponseYou've already chosen the best response.2
domain means the values which 'x' can take in that equation.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
do u see any values that 'x' can't take ?
 one year ago

suss Group TitleBest ResponseYou've already chosen the best response.0
i dont get it......??
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
(1)there is no denominator, if there was, then 'x' could not take values for which denominator=0
 one year ago

suss Group TitleBest ResponseYou've already chosen the best response.0
so ther is no soln for this??
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
(2) there is no \(\sqrt.\) sign, if there was , then 'x' cannot take values for which the expression under \(\sqrt{...}\)becomes negative.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
here, none of the 2 cases (1) or (2) arise. so 'x' can take all real values.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
so, domain is ALL real numbers R
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
understood ?
 one year ago

suss Group TitleBest ResponseYou've already chosen the best response.0
sorry i quite didnt get it
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
which par ?
 one year ago

suss Group TitleBest ResponseYou've already chosen the best response.0
x belongs to R then can we supoose any no we want in the place of x??
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yes, x can take any real value. u have options/choices ?
 one year ago

suss Group TitleBest ResponseYou've already chosen the best response.0
how wud u solve this prob?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
example : f(x) =1/ x x cannot take value =0 f(x) = 1/(x3) x cannot take value = 3 f(x) = sqrt{x4} x cannot take value less than 4
 one year ago

suss Group TitleBest ResponseYou've already chosen the best response.0
can u be mo` specific...?i cant understand
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
i just gave u specific examples. and there's nothing to solve, you can say 'x' can take all real values...
 one year ago

suss Group TitleBest ResponseYou've already chosen the best response.0
y did u add 3 in da denominator?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
By the way, all polynomials have the domain \((\infty,\infty)\) a.k.a \(\mathbb{R}\).
 one year ago

suss Group TitleBest ResponseYou've already chosen the best response.0
can u do the whole process??
 one year ago

BluFoot Group TitleBest ResponseYou've already chosen the best response.0
Domain means whenever the function exists. To figure this out, just find when the function does not exist, meaning when you're dividing by 0. In this case, you're never dividing by 0, so the function ALWAYS exists, so the domain is ]inf,inf[, also know as "R" for all real numbers. If say f(x) = 1/(x4), then the domain is ]inf,4[U]4,inf[, because the function exists everywhere except at x=4.
 one year ago
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