Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mustry

  • one year ago

any one help me abt calculus

  • This Question is Closed
  1. Nimi404
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Wat do mean

  2. Nimi404
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Calculate wat

  3. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If we have a product like y = (2x2 + 6x)(2x3 + 5x2)

  4. AravindG
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you need differential?

  5. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    d(uv)dx=udvdx+vdudx

  6. AravindG
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    if you need to differentiate use product rule

  7. Nimi404
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hey Aravin you again

  8. AravindG
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yep apply that

  9. AravindG
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @Nimi404 calculus is higher mathematics it doesnt mean calculate :P

  10. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how do derive this formula

  11. AravindG
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you mean you need to derive product rule ?

  12. Nimi404
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ooh then

  13. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Find the derivative of y = (x3 − 6x)(2 − 4x3)

  14. AravindG
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    confused ...can u be clear ?

  15. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    please help me this

  16. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Find the derivative of y = (x3 − 6x)(2 − 4x3)

  17. Yahoo!
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    u know Product Rule ? @mustry

  18. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yap

  19. AravindG
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1356793984995:dw|

  20. AravindG
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    where i took x^3-6x as first function and 2-4x^3 as second function

  21. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then

  22. AravindG
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    then used product rule

  23. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thankx but can u derive it product rule?

  24. Callisto
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Derive the product rule?

  25. mustry
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  26. Callisto
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay...*Take a deep breath*\[\frac{d}{dx}(uv)\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)v(x+h)-u(x)v(x)}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)v(x+h)\color{red}{+u(x+h)v(x)-u(x+h)v(x)}-u(x)v(x)}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)[v(x+h)+v(x)]-v(x)[u(x+h)-u(x)]}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)[v(x+h)+v(x)]}{h}-\lim_{h \rightarrow 0}\frac{v(x)[u(x+h)-u(x)]}{h}\]\[=\lim_{h \rightarrow 0}u(x+h)\lim_{h \rightarrow 0}\frac{v(x+h)+v(x)}{h}-v(x)\lim_{h \rightarrow 0}\frac{u(x+h)-u(x)}{h}\]\[=u(x)v'(x)+u'(x)v(x)\]

  27. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.