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mustry
 one year ago
Best ResponseYou've already chosen the best response.0If we have a product like y = (2x2 + 6x)(2x3 + 5x2)

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2you need differential?

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2if you need to differentiate use product rule

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2@Nimi404 calculus is higher mathematics it doesnt mean calculate :P

mustry
 one year ago
Best ResponseYou've already chosen the best response.0how do derive this formula

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2you mean you need to derive product rule ?

mustry
 one year ago
Best ResponseYou've already chosen the best response.0Find the derivative of y = (x3 − 6x)(2 − 4x3)

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2confused ...can u be clear ?

mustry
 one year ago
Best ResponseYou've already chosen the best response.0Find the derivative of y = (x3 − 6x)(2 − 4x3)

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0u know Product Rule ? @mustry

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2dw:1356793984995:dw

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2where i took x^36x as first function and 24x^3 as second function

AravindG
 one year ago
Best ResponseYou've already chosen the best response.2then used product rule

mustry
 one year ago
Best ResponseYou've already chosen the best response.0thankx but can u derive it product rule?

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0Derive the product rule?

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0Okay...*Take a deep breath*\[\frac{d}{dx}(uv)\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)v(x+h)u(x)v(x)}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)v(x+h)\color{red}{+u(x+h)v(x)u(x+h)v(x)}u(x)v(x)}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)[v(x+h)+v(x)]v(x)[u(x+h)u(x)]}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)[v(x+h)+v(x)]}{h}\lim_{h \rightarrow 0}\frac{v(x)[u(x+h)u(x)]}{h}\]\[=\lim_{h \rightarrow 0}u(x+h)\lim_{h \rightarrow 0}\frac{v(x+h)+v(x)}{h}v(x)\lim_{h \rightarrow 0}\frac{u(x+h)u(x)}{h}\]\[=u(x)v'(x)+u'(x)v(x)\]
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