Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Nimi404 Group TitleBest ResponseYou've already chosen the best response.0
Wat do mean
 one year ago

Nimi404 Group TitleBest ResponseYou've already chosen the best response.0
Calculate wat
 one year ago

mustry Group TitleBest ResponseYou've already chosen the best response.0
If we have a product like y = (2x2 + 6x)(2x3 + 5x2)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
you need differential?
 one year ago

mustry Group TitleBest ResponseYou've already chosen the best response.0
d(uv)dx=udvdx+vdudx
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
if you need to differentiate use product rule
 one year ago

Nimi404 Group TitleBest ResponseYou've already chosen the best response.0
Hey Aravin you again
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
yep apply that
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
@Nimi404 calculus is higher mathematics it doesnt mean calculate :P
 one year ago

mustry Group TitleBest ResponseYou've already chosen the best response.0
how do derive this formula
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
you mean you need to derive product rule ?
 one year ago

mustry Group TitleBest ResponseYou've already chosen the best response.0
Find the derivative of y = (x3 − 6x)(2 − 4x3)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
confused ...can u be clear ?
 one year ago

mustry Group TitleBest ResponseYou've already chosen the best response.0
please help me this
 one year ago

mustry Group TitleBest ResponseYou've already chosen the best response.0
Find the derivative of y = (x3 − 6x)(2 − 4x3)
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
u know Product Rule ? @mustry
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
dw:1356793984995:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
where i took x^36x as first function and 24x^3 as second function
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
then used product rule
 one year ago

mustry Group TitleBest ResponseYou've already chosen the best response.0
thankx but can u derive it product rule?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Derive the product rule?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Okay...*Take a deep breath*\[\frac{d}{dx}(uv)\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)v(x+h)u(x)v(x)}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)v(x+h)\color{red}{+u(x+h)v(x)u(x+h)v(x)}u(x)v(x)}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)[v(x+h)+v(x)]v(x)[u(x+h)u(x)]}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)[v(x+h)+v(x)]}{h}\lim_{h \rightarrow 0}\frac{v(x)[u(x+h)u(x)]}{h}\]\[=\lim_{h \rightarrow 0}u(x+h)\lim_{h \rightarrow 0}\frac{v(x+h)+v(x)}{h}v(x)\lim_{h \rightarrow 0}\frac{u(x+h)u(x)}{h}\]\[=u(x)v'(x)+u'(x)v(x)\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.