anonymous
  • anonymous
any one help me abt calculus
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Wat do mean
anonymous
  • anonymous
Calculate wat
anonymous
  • anonymous
If we have a product like y = (2x2 + 6x)(2x3 + 5x2)

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More answers

AravindG
  • AravindG
you need differential?
anonymous
  • anonymous
d(uv)dx=udvdx+vdudx
AravindG
  • AravindG
if you need to differentiate use product rule
anonymous
  • anonymous
Hey Aravin you again
AravindG
  • AravindG
yep apply that
AravindG
  • AravindG
@Nimi404 calculus is higher mathematics it doesnt mean calculate :P
anonymous
  • anonymous
how do derive this formula
AravindG
  • AravindG
you mean you need to derive product rule ?
anonymous
  • anonymous
Ooh then
anonymous
  • anonymous
Find the derivative of y = (x3 − 6x)(2 − 4x3)
AravindG
  • AravindG
confused ...can u be clear ?
anonymous
  • anonymous
please help me this
anonymous
  • anonymous
Find the derivative of y = (x3 − 6x)(2 − 4x3)
anonymous
  • anonymous
u know Product Rule ? @mustry
anonymous
  • anonymous
yap
AravindG
  • AravindG
|dw:1356793984995:dw|
AravindG
  • AravindG
where i took x^3-6x as first function and 2-4x^3 as second function
anonymous
  • anonymous
then
AravindG
  • AravindG
then used product rule
anonymous
  • anonymous
thankx but can u derive it product rule?
Callisto
  • Callisto
Derive the product rule?
anonymous
  • anonymous
yes
Callisto
  • Callisto
Okay...*Take a deep breath*\[\frac{d}{dx}(uv)\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)v(x+h)-u(x)v(x)}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)v(x+h)\color{red}{+u(x+h)v(x)-u(x+h)v(x)}-u(x)v(x)}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)[v(x+h)+v(x)]-v(x)[u(x+h)-u(x)]}{h}\]\[=\lim_{h \rightarrow 0}\frac{u(x+h)[v(x+h)+v(x)]}{h}-\lim_{h \rightarrow 0}\frac{v(x)[u(x+h)-u(x)]}{h}\]\[=\lim_{h \rightarrow 0}u(x+h)\lim_{h \rightarrow 0}\frac{v(x+h)+v(x)}{h}-v(x)\lim_{h \rightarrow 0}\frac{u(x+h)-u(x)}{h}\]\[=u(x)v'(x)+u'(x)v(x)\]

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