BelleFlower
Please wait for image. Logarithms



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BelleFlower
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hartnn
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which one ?

BelleFlower
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Q16

hartnn
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for part (i), take log on both sides,
log p=.... ?

BelleFlower
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lg p = lg a^loga x ?

hartnn
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yes, now use, \(\log m^n=m \log n\)

hartnn
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sorry, n log m

hartnn
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what u get ?

BelleFlower
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lg p = loga x * lg a

hartnn
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write log, not lg
now use,
\(\huge \log_ab=\frac{\log b}{\log a}\)
so what is log_a x = ??

BelleFlower
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log x / log a

hartnn
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now substitute that in
log p = loga x * log a

BelleFlower
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I'm not sure what to do but is it:
log p = (log x/log a) * log a ?

hartnn
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really ?
just cancel out log a from numerator and denominator....
what remains ??

hartnn
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and yes, its that

hartnn
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shall i write out all steps ??

BelleFlower
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Oh wait I got it ><' Thank you so much! :)

hartnn
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u want part 2 also ??

BelleFlower
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Yup

hartnn
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\(If, x=\log_ab \implies b=a^x\)
so what about , q=log_4 3 ??

BelleFlower
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3 = 4^x

hartnn
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u mean 3=4^q ??

BelleFlower
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sorry yup

hartnn
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now u need 3^(1/q) =... ?
so what will u do ??

BelleFlower
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I'm not sure..?

hartnn
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raise both sides to (1/q) exponent...

BelleFlower
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How do you do that sorry

hartnn
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\(\huge 3^{(1/q)}= (4^q)^{1/q}\)

hartnn
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\(\huge (4^q)^{1/q}=.....?\)

BelleFlower
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4

BelleFlower
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right?

hartnn
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yes.

hartnn
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and you are done ..

BelleFlower
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okay thanks a lot!

hartnn
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welcome ^_^