anonymous
  • anonymous
Please wait for image. Logarithms
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
hartnn
  • hartnn
which one ?
anonymous
  • anonymous
Q16

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hartnn
  • hartnn
for part (i), take log on both sides, log p=.... ?
anonymous
  • anonymous
lg p = lg a^loga x ?
hartnn
  • hartnn
yes, now use, \(\log m^n=m \log n\)
hartnn
  • hartnn
sorry, n log m
hartnn
  • hartnn
what u get ?
anonymous
  • anonymous
lg p = loga x * lg a
hartnn
  • hartnn
write log, not lg now use, \(\huge \log_ab=\frac{\log b}{\log a}\) so what is log_a x = ??
anonymous
  • anonymous
log x / log a
hartnn
  • hartnn
now substitute that in log p = loga x * log a
anonymous
  • anonymous
I'm not sure what to do but is it: log p = (log x/log a) * log a ?
hartnn
  • hartnn
really ? just cancel out log a from numerator and denominator.... what remains ??
hartnn
  • hartnn
and yes, its that
hartnn
  • hartnn
shall i write out all steps ??
anonymous
  • anonymous
Oh wait I got it ><' Thank you so much! :)
hartnn
  • hartnn
u want part 2 also ??
anonymous
  • anonymous
Yup
hartnn
  • hartnn
\(If, x=\log_ab \implies b=a^x\) so what about , q=log_4 3 ??
anonymous
  • anonymous
3 = 4^x
hartnn
  • hartnn
u mean 3=4^q ??
anonymous
  • anonymous
sorry yup
hartnn
  • hartnn
now u need 3^(1/q) =... ? so what will u do ??
anonymous
  • anonymous
I'm not sure..?
hartnn
  • hartnn
raise both sides to (1/q) exponent...
anonymous
  • anonymous
How do you do that sorry
hartnn
  • hartnn
\(\huge 3^{(1/q)}= (4^q)^{1/q}\)
hartnn
  • hartnn
\(\huge (4^q)^{1/q}=.....?\)
anonymous
  • anonymous
4
anonymous
  • anonymous
right?
hartnn
  • hartnn
yes.
hartnn
  • hartnn
and you are done ..
anonymous
  • anonymous
okay thanks a lot!
hartnn
  • hartnn
welcome ^_^

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