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anonymous
 4 years ago
Please wait for image. Logarithms
anonymous
 4 years ago
Please wait for image. Logarithms

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hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1for part (i), take log on both sides, log p=.... ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1yes, now use, \(\log m^n=m \log n\)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1write log, not lg now use, \(\huge \log_ab=\frac{\log b}{\log a}\) so what is log_a x = ??

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1now substitute that in log p = loga x * log a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm not sure what to do but is it: log p = (log x/log a) * log a ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1really ? just cancel out log a from numerator and denominator.... what remains ??

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1shall i write out all steps ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh wait I got it ><' Thank you so much! :)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1\(If, x=\log_ab \implies b=a^x\) so what about , q=log_4 3 ??

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1now u need 3^(1/q) =... ? so what will u do ??

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1raise both sides to (1/q) exponent...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How do you do that sorry

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1\(\huge 3^{(1/q)}= (4^q)^{1/q}\)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1\(\huge (4^q)^{1/q}=.....?\)
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