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BelleFlower

  • 2 years ago

Please wait for image. Logarithms

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  1. BelleFlower
    • 2 years ago
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  2. hartnn
    • 2 years ago
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    which one ?

  3. BelleFlower
    • 2 years ago
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    Q16

  4. hartnn
    • 2 years ago
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    for part (i), take log on both sides, log p=.... ?

  5. BelleFlower
    • 2 years ago
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    lg p = lg a^loga x ?

  6. hartnn
    • 2 years ago
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    yes, now use, \(\log m^n=m \log n\)

  7. hartnn
    • 2 years ago
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    sorry, n log m

  8. hartnn
    • 2 years ago
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    what u get ?

  9. BelleFlower
    • 2 years ago
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    lg p = loga x * lg a

  10. hartnn
    • 2 years ago
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    write log, not lg now use, \(\huge \log_ab=\frac{\log b}{\log a}\) so what is log_a x = ??

  11. BelleFlower
    • 2 years ago
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    log x / log a

  12. hartnn
    • 2 years ago
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    now substitute that in log p = loga x * log a

  13. BelleFlower
    • 2 years ago
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    I'm not sure what to do but is it: log p = (log x/log a) * log a ?

  14. hartnn
    • 2 years ago
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    really ? just cancel out log a from numerator and denominator.... what remains ??

  15. hartnn
    • 2 years ago
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    and yes, its that

  16. hartnn
    • 2 years ago
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    shall i write out all steps ??

  17. BelleFlower
    • 2 years ago
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    Oh wait I got it ><' Thank you so much! :)

  18. hartnn
    • 2 years ago
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    u want part 2 also ??

  19. BelleFlower
    • 2 years ago
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    Yup

  20. hartnn
    • 2 years ago
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    \(If, x=\log_ab \implies b=a^x\) so what about , q=log_4 3 ??

  21. BelleFlower
    • 2 years ago
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    3 = 4^x

  22. hartnn
    • 2 years ago
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    u mean 3=4^q ??

  23. BelleFlower
    • 2 years ago
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    sorry yup

  24. hartnn
    • 2 years ago
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    now u need 3^(1/q) =... ? so what will u do ??

  25. BelleFlower
    • 2 years ago
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    I'm not sure..?

  26. hartnn
    • 2 years ago
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    raise both sides to (1/q) exponent...

  27. BelleFlower
    • 2 years ago
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    How do you do that sorry

  28. hartnn
    • 2 years ago
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    \(\huge 3^{(1/q)}= (4^q)^{1/q}\)

  29. hartnn
    • 2 years ago
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    \(\huge (4^q)^{1/q}=.....?\)

  30. BelleFlower
    • 2 years ago
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    4

  31. BelleFlower
    • 2 years ago
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    right?

  32. hartnn
    • 2 years ago
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    yes.

  33. hartnn
    • 2 years ago
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    and you are done ..

  34. BelleFlower
    • 2 years ago
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    okay thanks a lot!

  35. hartnn
    • 2 years ago
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    welcome ^_^

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