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Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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which one ?
Q16

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Other answers:

for part (i), take log on both sides, log p=.... ?
lg p = lg a^loga x ?
yes, now use, \(\log m^n=m \log n\)
sorry, n log m
what u get ?
lg p = loga x * lg a
write log, not lg now use, \(\huge \log_ab=\frac{\log b}{\log a}\) so what is log_a x = ??
log x / log a
now substitute that in log p = loga x * log a
I'm not sure what to do but is it: log p = (log x/log a) * log a ?
really ? just cancel out log a from numerator and denominator.... what remains ??
and yes, its that
shall i write out all steps ??
Oh wait I got it ><' Thank you so much! :)
u want part 2 also ??
Yup
\(If, x=\log_ab \implies b=a^x\) so what about , q=log_4 3 ??
3 = 4^x
u mean 3=4^q ??
sorry yup
now u need 3^(1/q) =... ? so what will u do ??
I'm not sure..?
raise both sides to (1/q) exponent...
How do you do that sorry
\(\huge 3^{(1/q)}= (4^q)^{1/q}\)
\(\huge (4^q)^{1/q}=.....?\)
4
right?
yes.
and you are done ..
okay thanks a lot!
welcome ^_^

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