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hartnnBest ResponseYou've already chosen the best response.1
for part (i), take log on both sides, log p=.... ?
 one year ago

BelleFlowerBest ResponseYou've already chosen the best response.0
lg p = lg a^loga x ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
yes, now use, \(\log m^n=m \log n\)
 one year ago

BelleFlowerBest ResponseYou've already chosen the best response.0
lg p = loga x * lg a
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
write log, not lg now use, \(\huge \log_ab=\frac{\log b}{\log a}\) so what is log_a x = ??
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
now substitute that in log p = loga x * log a
 one year ago

BelleFlowerBest ResponseYou've already chosen the best response.0
I'm not sure what to do but is it: log p = (log x/log a) * log a ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
really ? just cancel out log a from numerator and denominator.... what remains ??
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
shall i write out all steps ??
 one year ago

BelleFlowerBest ResponseYou've already chosen the best response.0
Oh wait I got it ><' Thank you so much! :)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(If, x=\log_ab \implies b=a^x\) so what about , q=log_4 3 ??
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
now u need 3^(1/q) =... ? so what will u do ??
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
raise both sides to (1/q) exponent...
 one year ago

BelleFlowerBest ResponseYou've already chosen the best response.0
How do you do that sorry
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\huge 3^{(1/q)}= (4^q)^{1/q}\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\huge (4^q)^{1/q}=.....?\)
 one year ago

BelleFlowerBest ResponseYou've already chosen the best response.0
okay thanks a lot!
 one year ago
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