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patdistheman

  • 2 years ago

(H + 1) / 10 = B H = 100 B = 10.1 (Only the rounded down result is applicable.) Next Cycle H = 110 B = 11.11 (11) Next Cycle H = 121 B = 12.2 (12) Next Cycle H = 132 B = 13.3 (13) In this example. Starting H = 100 and Cycles = 3 the result is B = 13.3. How do you determine a formula that allows you to pick a starting number for H and the number of cycles and generate B?

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  1. LogicalApple
    • 2 years ago
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    Can this be a two part function? Or does it have to be one function?

  2. patdistheman
    • 2 years ago
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    I do not understand what that means.

  3. patdistheman
    • 2 years ago
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    As far as I am concerned anything that will generate the answer.

  4. LogicalApple
    • 2 years ago
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    If you're looking for the solutions in parentheses then you are looking for integer division. If you use the floor function then you will obtain what you are looking for. Have you seen the floor function before?

  5. patdistheman
    • 2 years ago
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    The floor function generates a rounded down number?

  6. LogicalApple
    • 2 years ago
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    Yes, it basically truncates (gets rid of) the decimal.

  7. patdistheman
    • 2 years ago
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    I am attempting to determine if lets say there were 1072 cycles... what would b equal?

  8. LogicalApple
    • 2 years ago
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    I see what you are saying. Hm.

  9. patdistheman
    • 2 years ago
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    I am not interested so much in the answer as to what B is as to how to go about solving this problem of generating the formula to determine any answer for B.

  10. LogicalApple
    • 2 years ago
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    I can think of a recursive formula...

  11. patdistheman
    • 2 years ago
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    I would greatly appreciate that if you could show me how you generated it.

  12. LogicalApple
    • 2 years ago
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    |dw:1356826201787:dw|

  13. LogicalApple
    • 2 years ago
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    Since the result of each cycle is the input into the next one, the function can be defined recursively.

  14. patdistheman
    • 2 years ago
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    I am not certain how to compute that formula.

  15. LogicalApple
    • 2 years ago
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    That is the problem with it -- it is recursive so there is no straightforward way to solve it. You would need to know the value of every cycle prior to the last cycle.

  16. patdistheman
    • 2 years ago
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    Is there a way to put that formula into a spreadsheet?

  17. LogicalApple
    • 2 years ago
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    |dw:1356828418136:dw| This corrected version of the recursion yields correct results. I am not sure how to insert something like this into a spreadsheet. However, a programming routine could help. Unfortunately for larger and larger cycles, more recursion results in longer processing and more memory demand.

  18. LogicalApple
    • 2 years ago
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    Here Ba is the (rounded off) value of B on the ath cycle. So, B_10 would give you the result of the 10th cycle.

  19. patdistheman
    • 2 years ago
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    I have to run but I will be back shortly. Can you show me a step by step solution for that formula? I am not certain how the mechanics of that work.

  20. LogicalApple
    • 2 years ago
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    Let's say you want to know the 4th cycle. B4 = [H3 + B3 + 1]/10 H3 = H2 + B2 B3 = [H2 + B2 + 1]/10 H2 = H1 + B1 B3 = [H1 + B1 + B2 + 1]/10 H1 = H0 + B0 = 100 + 10 = 110 B0 = 10 Thus H2 = 110 + 10 = 120 B1 = [H0 + B0 + 1]/10 = 11 B2 = [H1 + B1 + 1]/10 = 12 So far we have H2 and B2, so we can solve for B3 B3 = [H2 + B2 + 1]/10 = 13 And H3 = H2 + B2 = 120 + 12 = 132 So for B4... B4 = [H3 + B3 + 1]/10 B4 = [(132 + 13)/10] = 14 It's a lengthy process and a computer program would be advised to calculate any further values this way.

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