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dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1first set equal to zero second find discriminate (b^2 4ac) third, if discriminate >0 : 2 real solutions if discriminate =0: 1 real solution if discriminate <0 : no real solutions

angelwings996
 2 years ago
Best ResponseYou've already chosen the best response.0would the equation be 11x^2  x  11 = 0 ?

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1yes or you can get rid of the neg > 11x^2 +x+11 = 0

angelwings996
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, now what would I do?

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1find Discriminant http://en.wikipedia.org/wiki/Discriminant

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then calculate \(b^24ac=...?\)

angelwings996
 2 years ago
Best ResponseYou've already chosen the best response.0don't I already have a, b, and c so would I just substitute them into b^2  4ac ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1what u got, a=..? b=...?c=..?

angelwings996
 2 years ago
Best ResponseYou've already chosen the best response.0doesn't a = 11, b = 1, and c = 11 ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1thats correct, now as @dumbcow said, u just need to find whether b^24ac is positive or negative...

angelwings996
 2 years ago
Best ResponseYou've already chosen the best response.0so if I plug it in would it be like this .... \[1 ^{2}  4(11)(11)\]

angelwings996
 2 years ago
Best ResponseYou've already chosen the best response.0okay so \[1^{2} = 1 and 4(11) = 44(11) = 484\] Then you would subtract 484 from 1 which gives you 483, right ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1yes, so how many real solutions ?

angelwings996
 2 years ago
Best ResponseYou've already chosen the best response.0since 483 is less than 0 would it be no real solutions?

angelwings996
 2 years ago
Best ResponseYou've already chosen the best response.0Okay thank you so much for both of your helps!
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