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angelwings996
Group Title
What is the number of real solutions?
11x^2 = x + 11
 one year ago
 one year ago
angelwings996 Group Title
What is the number of real solutions? 11x^2 = x + 11
 one year ago
 one year ago

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dumbcow Group TitleBest ResponseYou've already chosen the best response.1
first set equal to zero second find discriminate (b^2 4ac) third, if discriminate >0 : 2 real solutions if discriminate =0: 1 real solution if discriminate <0 : no real solutions
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
would the equation be 11x^2  x  11 = 0 ?
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
yes or you can get rid of the neg > 11x^2 +x+11 = 0
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay, now what would I do?
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
find Discriminant http://en.wikipedia.org/wiki/Discriminant
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then calculate \(b^24ac=...?\)
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
don't I already have a, b, and c so would I just substitute them into b^2  4ac ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what u got, a=..? b=...?c=..?
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
doesn't a = 11, b = 1, and c = 11 ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
thats correct, now as @dumbcow said, u just need to find whether b^24ac is positive or negative...
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
so if I plug it in would it be like this .... \[1 ^{2}  4(11)(11)\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, go on.
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
okay so \[1^{2} = 1 and 4(11) = 44(11) = 484\] Then you would subtract 484 from 1 which gives you 483, right ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, so how many real solutions ?
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
since 483 is less than 0 would it be no real solutions?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
absolutely correct :)
 one year ago

angelwings996 Group TitleBest ResponseYou've already chosen the best response.0
Okay thank you so much for both of your helps!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 one year ago
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