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dumbcowBest ResponseYou've already chosen the best response.1
first set equal to zero second find discriminate (b^2 4ac) third, if discriminate >0 : 2 real solutions if discriminate =0: 1 real solution if discriminate <0 : no real solutions
 one year ago

angelwings996Best ResponseYou've already chosen the best response.0
would the equation be 11x^2  x  11 = 0 ?
 one year ago

dumbcowBest ResponseYou've already chosen the best response.1
yes or you can get rid of the neg > 11x^2 +x+11 = 0
 one year ago

angelwings996Best ResponseYou've already chosen the best response.0
Okay, now what would I do?
 one year ago

dumbcowBest ResponseYou've already chosen the best response.1
find Discriminant http://en.wikipedia.org/wiki/Discriminant
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then calculate \(b^24ac=...?\)
 one year ago

angelwings996Best ResponseYou've already chosen the best response.0
don't I already have a, b, and c so would I just substitute them into b^2  4ac ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
what u got, a=..? b=...?c=..?
 one year ago

angelwings996Best ResponseYou've already chosen the best response.0
doesn't a = 11, b = 1, and c = 11 ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
thats correct, now as @dumbcow said, u just need to find whether b^24ac is positive or negative...
 one year ago

angelwings996Best ResponseYou've already chosen the best response.0
so if I plug it in would it be like this .... \[1 ^{2}  4(11)(11)\]
 one year ago

angelwings996Best ResponseYou've already chosen the best response.0
okay so \[1^{2} = 1 and 4(11) = 44(11) = 484\] Then you would subtract 484 from 1 which gives you 483, right ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
yes, so how many real solutions ?
 one year ago

angelwings996Best ResponseYou've already chosen the best response.0
since 483 is less than 0 would it be no real solutions?
 one year ago

angelwings996Best ResponseYou've already chosen the best response.0
Okay thank you so much for both of your helps!
 one year ago
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