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would the equation be -11x^2 - x - 11 = 0 ?

yes or you can get rid of the neg --> 11x^2 +x+11 = 0

Okay, now what would I do?

find Discriminant
http://en.wikipedia.org/wiki/Discriminant

Compare your quadratic equation with \(ax^2+bx+c=0\)
find a,b,c
then calculate \(b^2-4ac=...?\)

don't I already have a, b, and c so would I just substitute them into b^2 - 4ac ?

what u got, a=..?
b=...?c=..?

doesn't a = 11, b = 1, and c = 11 ?

so if I plug it in would it be like this ....
\[1 ^{2} - 4(11)(11)\]

yes, go on.

yes, so how many real solutions ?

since -483 is less than 0 would it be no real solutions?

absolutely correct :)

Okay thank you so much for both of your helps!

welcome ^_^