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zeig_101

  • one year ago

http://imageshack.us/a/img600/9208/46482438201155754pm1773.png If ON = 8x – 8, LM = 7x + 4, NM = x – 5, and OL = 3y – 6, find the values of x and y for which LMNO must be a parallelogram. The diagram is not drawn to scale.

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  1. hartnn
    • one year ago
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    hint : opposite sides of parallelogram are equal.

  2. hartnn
    • one year ago
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    so, ON =LM can u form an equation ?

  3. zeig_101
    • one year ago
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    8x-8=7x+4

  4. hartnn
    • one year ago
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    thats correct! now can u solve that for x ?

  5. zeig_101
    • one year ago
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    8x=7x+12 x=12

  6. hartnn
    • one year ago
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    very good! now other pair of opposite side is also equal. NM =OL equation ?

  7. viniterranova
    • one year ago
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    Great work zeig_101

  8. zeig_101
    • one year ago
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    NM = x – 5, and OL = 3y – 6, x-5=3y-6 12-5=3y-6 7=3y-6 13=3y

  9. zeig_101
    • one year ago
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    y=4.3333333

  10. viniterranova
    • one year ago
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    You are in the right way zeig_101.

  11. hartnn
    • one year ago
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    yes , you are \(\large \checkmark\)

  12. zeig_101
    • one year ago
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    is that all I need?

  13. hartnn
    • one year ago
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    yes, you can keep, y= 13/3 or 4.3333 is also ok.

  14. zeig_101
    • one year ago
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    so y=4.repeated 3, and x=12?

  15. hartnn
    • one year ago
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    yes, exactly.

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