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BelleFlower

  • 2 years ago

Logarithms! Wait for image please!

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  1. BelleFlower
    • 2 years ago
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    Part c!

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  2. hartnn
    • 2 years ago
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    hint : write \(2=\log_2 2^2\)

  3. BelleFlower
    • 2 years ago
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    This is what I have done so far: log_2 (x - 1)^2 = log_2 4 + log_2 (x+2) (x-1)^2 = 4 + x + 2 x^2 - 3x - 7 = 0

  4. BelleFlower
    • 2 years ago
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    Is that correct?

  5. hartnn
    • 2 years ago
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    no....

  6. hartnn
    • 2 years ago
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    (x-1)^2 = 4 ( x + 2 ) u got how ?

  7. BelleFlower
    • 2 years ago
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    Oh wait is it: (x - 1)^2 = 4x + 8 or am I still wrong?

  8. BelleFlower
    • 2 years ago
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    @hartnn

  9. hartnn
    • 2 years ago
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    now correct.

  10. BelleFlower
    • 2 years ago
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    So if I solve that I should be able to get the answer right?

  11. BelleFlower
    • 2 years ago
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    Okay thanks! :)

  12. hartnn
    • 2 years ago
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    yes, welcome ^_^

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spraguer (Moderator)
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