anonymous
  • anonymous
Logarithms! Wait for image please!
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Part c!
1 Attachment
hartnn
  • hartnn
hint : write \(2=\log_2 2^2\)
anonymous
  • anonymous
This is what I have done so far: log_2 (x - 1)^2 = log_2 4 + log_2 (x+2) (x-1)^2 = 4 + x + 2 x^2 - 3x - 7 = 0

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anonymous
  • anonymous
Is that correct?
hartnn
  • hartnn
no....
hartnn
  • hartnn
(x-1)^2 = 4 ( x + 2 ) u got how ?
anonymous
  • anonymous
Oh wait is it: (x - 1)^2 = 4x + 8 or am I still wrong?
anonymous
  • anonymous
@hartnn
hartnn
  • hartnn
now correct.
anonymous
  • anonymous
So if I solve that I should be able to get the answer right?
anonymous
  • anonymous
Okay thanks! :)
hartnn
  • hartnn
yes, welcome ^_^

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