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LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.0Like \[a ^{m + n} = a ^{m}a ^{n} ?\]

itsjustme_lol
 one year ago
Best ResponseYou've already chosen the best response.0idk. hang on let me seee lol

itsjustme_lol
 one year ago
Best ResponseYou've already chosen the best response.0thats one of them problems it gives me.

KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.2For that problem, there's two laws that you need to be familiar with. Law 1:\[\large (a\cdot b)^n=a^n\cdot b^n\] Law 2: \[\large (a^n)^m=a^{n\cdot m}\]Using these, can you find the solution to your problem.

itsjustme_lol
 one year ago
Best ResponseYou've already chosen the best response.0ok that makes a little bit more sense . so could you help me solve that problem that I posted?

KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.2Sure. First, the correct formatting is \[\large (3a^4)^3\]correct?

KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.2First, we use the first law I mentioned. So \[\large (3a^4)^3=3^3\cdot(a^4)^3\]Now, use law 2 to simplify \((a^4)^3\). Can you tell me what you get?

itsjustme_lol
 one year ago
Best ResponseYou've already chosen the best response.0ok give me a sec

itsjustme_lol
 one year ago
Best ResponseYou've already chosen the best response.0(a)^7 ?? i think thats totaly wrong

KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.2It's the second one. Good job! That means, we've simplified to \[\large 3^3\cdot a^{12} \small .\]Now just find \(3^3\), and you're done.

itsjustme_lol
 one year ago
Best ResponseYou've already chosen the best response.0with the 3^3 do I multiply that..is it 9?

KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.2\(3^3=(3\cdot3)\cdot3=9\cdot3=27\)

itsjustme_lol
 one year ago
Best ResponseYou've already chosen the best response.0oh i see what you did there, i seee my mistake

itsjustme_lol
 one year ago
Best ResponseYou've already chosen the best response.0so its (a^12)27?

precal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1356824001142:dwalso, parenthesis between the exponents remind me to multiply the powers, this is one of the ways I remember this law

KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.2You could write it as \(27\cdot a^{12}\) or \(a^{12}\cdot 27\). And if you have some trouble remembering the law, precal's way to do it an excellent way to remember.

precal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1356824081954:dwI always associated the laws with things I already know

itsjustme_lol
 one year ago
Best ResponseYou've already chosen the best response.0i wish I could give u guys both medals :p i appreicate both!!
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