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itsjustme_lol

  • one year ago

Laws of Exponents..im not understanding this

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  1. LogicalApple
    • one year ago
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    Like \[a ^{m + n} = a ^{m}a ^{n} ?\]

  2. itsjustme_lol
    • one year ago
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    idk. hang on let me seee lol

  3. itsjustme_lol
    • one year ago
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    (3a^4)3

  4. itsjustme_lol
    • one year ago
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    thats one of them problems it gives me.

  5. KingGeorge
    • one year ago
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    For that problem, there's two laws that you need to be familiar with. Law 1:\[\large (a\cdot b)^n=a^n\cdot b^n\] Law 2: \[\large (a^n)^m=a^{n\cdot m}\]Using these, can you find the solution to your problem.

  6. itsjustme_lol
    • one year ago
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    ok that makes a little bit more sense . so could you help me solve that problem that I posted?

  7. KingGeorge
    • one year ago
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    Sure. First, the correct formatting is \[\large (3a^4)^3\]correct?

  8. itsjustme_lol
    • one year ago
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    yes

  9. itsjustme_lol
    • one year ago
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    and thankyou!

  10. KingGeorge
    • one year ago
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    First, we use the first law I mentioned. So \[\large (3a^4)^3=3^3\cdot(a^4)^3\]Now, use law 2 to simplify \((a^4)^3\). Can you tell me what you get?

  11. itsjustme_lol
    • one year ago
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    ok give me a sec

  12. itsjustme_lol
    • one year ago
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    (a)^7 ?? i think thats totaly wrong

  13. itsjustme_lol
    • one year ago
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    unless is a^12

  14. KingGeorge
    • one year ago
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    It's the second one. Good job! That means, we've simplified to \[\large 3^3\cdot a^{12} \small .\]Now just find \(3^3\), and you're done.

  15. itsjustme_lol
    • one year ago
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    with the 3^3 do I multiply that..is it 9?

  16. KingGeorge
    • one year ago
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    \(3^3=(3\cdot3)\cdot3=9\cdot3=27\)

  17. itsjustme_lol
    • one year ago
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    oh i see what you did there, i seee my mistake

  18. itsjustme_lol
    • one year ago
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    so its (a^12)27?

  19. precal
    • one year ago
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    |dw:1356824001142:dw|also, parenthesis between the exponents remind me to multiply the powers, this is one of the ways I remember this law

  20. KingGeorge
    • one year ago
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    You could write it as \(27\cdot a^{12}\) or \(a^{12}\cdot 27\). And if you have some trouble remembering the law, precal's way to do it an excellent way to remember.

  21. precal
    • one year ago
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    |dw:1356824081954:dw|I always associated the laws with things I already know

  22. itsjustme_lol
    • one year ago
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    i wish I could give u guys both medals :p i appreicate both!!

  23. KingGeorge
    • one year ago
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    You're welcome.

  24. precal
    • one year ago
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    np yw

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