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LogicalApple
 2 years ago
Best ResponseYou've already chosen the best response.0Like \[a ^{m + n} = a ^{m}a ^{n} ?\]

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0idk. hang on let me seee lol

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0thats one of them problems it gives me.

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.2For that problem, there's two laws that you need to be familiar with. Law 1:\[\large (a\cdot b)^n=a^n\cdot b^n\] Law 2: \[\large (a^n)^m=a^{n\cdot m}\]Using these, can you find the solution to your problem.

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0ok that makes a little bit more sense . so could you help me solve that problem that I posted?

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.2Sure. First, the correct formatting is \[\large (3a^4)^3\]correct?

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.2First, we use the first law I mentioned. So \[\large (3a^4)^3=3^3\cdot(a^4)^3\]Now, use law 2 to simplify \((a^4)^3\). Can you tell me what you get?

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0(a)^7 ?? i think thats totaly wrong

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.2It's the second one. Good job! That means, we've simplified to \[\large 3^3\cdot a^{12} \small .\]Now just find \(3^3\), and you're done.

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0with the 3^3 do I multiply that..is it 9?

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.2\(3^3=(3\cdot3)\cdot3=9\cdot3=27\)

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0oh i see what you did there, i seee my mistake

precal
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1356824001142:dwalso, parenthesis between the exponents remind me to multiply the powers, this is one of the ways I remember this law

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.2You could write it as \(27\cdot a^{12}\) or \(a^{12}\cdot 27\). And if you have some trouble remembering the law, precal's way to do it an excellent way to remember.

precal
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1356824081954:dwI always associated the laws with things I already know

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0i wish I could give u guys both medals :p i appreicate both!!
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