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LogicalApple Group TitleBest ResponseYou've already chosen the best response.0
Like \[a ^{m + n} = a ^{m}a ^{n} ?\]
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
idk. hang on let me seee lol
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
(3a^4)3
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
thats one of them problems it gives me.
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.2
For that problem, there's two laws that you need to be familiar with. Law 1:\[\large (a\cdot b)^n=a^n\cdot b^n\] Law 2: \[\large (a^n)^m=a^{n\cdot m}\]Using these, can you find the solution to your problem.
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
ok that makes a little bit more sense . so could you help me solve that problem that I posted?
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.2
Sure. First, the correct formatting is \[\large (3a^4)^3\]correct?
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
and thankyou!
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.2
First, we use the first law I mentioned. So \[\large (3a^4)^3=3^3\cdot(a^4)^3\]Now, use law 2 to simplify \((a^4)^3\). Can you tell me what you get?
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
ok give me a sec
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
(a)^7 ?? i think thats totaly wrong
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
unless is a^12
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.2
It's the second one. Good job! That means, we've simplified to \[\large 3^3\cdot a^{12} \small .\]Now just find \(3^3\), and you're done.
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
with the 3^3 do I multiply that..is it 9?
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.2
\(3^3=(3\cdot3)\cdot3=9\cdot3=27\)
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
oh i see what you did there, i seee my mistake
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
so its (a^12)27?
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.1
dw:1356824001142:dwalso, parenthesis between the exponents remind me to multiply the powers, this is one of the ways I remember this law
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.2
You could write it as \(27\cdot a^{12}\) or \(a^{12}\cdot 27\). And if you have some trouble remembering the law, precal's way to do it an excellent way to remember.
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.1
dw:1356824081954:dwI always associated the laws with things I already know
 one year ago

itsjustme_lol Group TitleBest ResponseYou've already chosen the best response.0
i wish I could give u guys both medals :p i appreicate both!!
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.2
You're welcome.
 one year ago
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