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hartnn
 3 years ago
∫[(x + 1)/(x*(1 + x*e^x)²)]dx
hartnn
 3 years ago
∫[(x + 1)/(x*(1 + x*e^x)²)]dx

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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.5\(\huge \int \frac{x+1}{x(1+xe^x)^2}dx=..?\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.5partial fractions? or x= log y substitution or how ??

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.5for partial fractions, there should be linear expression, 1+xe^x is not linear....

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.0But you do have a function squared. wHICH You can expand to get a ^2x

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.5what would i take in numerator ?? if it were (x+1)^2, i would have taken A/(x+1) +B/(x+1)^2 ...

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, or Ax+B for numerator if you expand it.

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.0I think you can use Ax+B w/o expanding. haha. I'm just making guesses now. I don't have a pen within a 12 inch radius Lol

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.0But it looks like partial should work.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.5the answer suggested me partial, but how is the question....

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ A}{ x } + \frac{ Bx+C }{ (1+xe^x) }+...\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.5not justified, nor will give complete answer...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Right but what are the steps to derive this?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.5then partial fractions...

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.5\(\huge \int \frac{e^x(x+1)}{x.e^x(1+xe^x)^2}dx=\int \frac{dy}{y^2(y1)}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's not magic anymore .. :(
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