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 one year ago
find an equation of the normal line to the parabola y=x^28x+9 at point (3,6)... help me..
 one year ago
find an equation of the normal line to the parabola y=x^28x+9 at point (3,6)... help me..

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LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2Can you use calculus?

sha0403
 one year ago
Best ResponseYou've already chosen the best response.0how to use it? i don't know coz it do not give the value of x after differetiate.. so i don't know how to find m..

LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2What do you get for y'(x) in general?

LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2Perfect. This is the equation of the tangents of x^2  8x + 9. Let x = 3 and solve for y'(x) to get the tangent at that point.

LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2More specifically, y'(x) gives you the 'slope' of the tangent at x.

sha0403
 one year ago
Best ResponseYou've already chosen the best response.0so after that if i get the value of m,, should i substitute the (3,6) again tu find c?

LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2Let's assume you found the slope at x = 3. This is the slope of the tangent line. The slope of the normal line would be perpendicular to it. What is the relationship of slopes between perpendicular lines?

sha0403
 one year ago
Best ResponseYou've already chosen the best response.0so, it share the same value of x? right?

LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2Well, the point (3, 6) will be the same. The only difference is, the slope of the normal line will be the negative reciprocal of the slope of the tangent line (since they are perpendicular).

LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2dw:1356835091005:dw

LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2The point there is supposed to represent (3, 6). The tangent line is drawn with a slope of m = y'(3), and the normal line is also drawn perpendicular to it.

sha0403
 one year ago
Best ResponseYou've already chosen the best response.0ok i understand now...thanks for your explanation....

LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2y'(3) = 2(3)  8 = 2 = slope of the tangent line Thus the slope of the normal line would be 1/2 and pass through (3, 6).

sha0403
 one year ago
Best ResponseYou've already chosen the best response.0but i little bit confuse,, how do u know the shape of graph was perpendicular?

LogicalApple
 one year ago
Best ResponseYou've already chosen the best response.2Do you mean the direction of the normal line? A normal line is just a line perpendicular to whatever shape we're talking about. More specifically, a normal line is perpendicular to a tangent line.

sha0403
 one year ago
Best ResponseYou've already chosen the best response.0ok i understand..thank u,, :)
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