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sha0403
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find an equation of the normal line to the parabola y=x^28x+9 at point (3,6)... help me..
 one year ago
 one year ago
sha0403 Group Title
find an equation of the normal line to the parabola y=x^28x+9 at point (3,6)... help me..
 one year ago
 one year ago

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LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
Can you use calculus?
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
how to use it? i don't know coz it do not give the value of x after differetiate.. so i don't know how to find m..
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
What do you get for y'(x) in general?
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
i get 2x 8...
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
Perfect. This is the equation of the tangents of x^2  8x + 9. Let x = 3 and solve for y'(x) to get the tangent at that point.
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
More specifically, y'(x) gives you the 'slope' of the tangent at x.
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
so after that if i get the value of m,, should i substitute the (3,6) again tu find c?
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
Let's assume you found the slope at x = 3. This is the slope of the tangent line. The slope of the normal line would be perpendicular to it. What is the relationship of slopes between perpendicular lines?
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
so, it share the same value of x? right?
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
Well, the point (3, 6) will be the same. The only difference is, the slope of the normal line will be the negative reciprocal of the slope of the tangent line (since they are perpendicular).
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
dw:1356835091005:dw
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
The point there is supposed to represent (3, 6). The tangent line is drawn with a slope of m = y'(3), and the normal line is also drawn perpendicular to it.
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
ok i understand now...thanks for your explanation....
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
y'(3) = 2(3)  8 = 2 = slope of the tangent line Thus the slope of the normal line would be 1/2 and pass through (3, 6).
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
but i little bit confuse,, how do u know the shape of graph was perpendicular?
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.2
Do you mean the direction of the normal line? A normal line is just a line perpendicular to whatever shape we're talking about. More specifically, a normal line is perpendicular to a tangent line.
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
ok i understand..thank u,, :)
 one year ago
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