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anonymous
 3 years ago
find an equation of the normal line to the parabola y=x^28x+9 at point (3,6)... help me..
anonymous
 3 years ago
find an equation of the normal line to the parabola y=x^28x+9 at point (3,6)... help me..

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you use calculus?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how to use it? i don't know coz it do not give the value of x after differetiate.. so i don't know how to find m..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do you get for y'(x) in general?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Perfect. This is the equation of the tangents of x^2  8x + 9. Let x = 3 and solve for y'(x) to get the tangent at that point.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0More specifically, y'(x) gives you the 'slope' of the tangent at x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so after that if i get the value of m,, should i substitute the (3,6) again tu find c?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Let's assume you found the slope at x = 3. This is the slope of the tangent line. The slope of the normal line would be perpendicular to it. What is the relationship of slopes between perpendicular lines?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, it share the same value of x? right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well, the point (3, 6) will be the same. The only difference is, the slope of the normal line will be the negative reciprocal of the slope of the tangent line (since they are perpendicular).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1356835091005:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The point there is supposed to represent (3, 6). The tangent line is drawn with a slope of m = y'(3), and the normal line is also drawn perpendicular to it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok i understand now...thanks for your explanation....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y'(3) = 2(3)  8 = 2 = slope of the tangent line Thus the slope of the normal line would be 1/2 and pass through (3, 6).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but i little bit confuse,, how do u know the shape of graph was perpendicular?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you mean the direction of the normal line? A normal line is just a line perpendicular to whatever shape we're talking about. More specifically, a normal line is perpendicular to a tangent line.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok i understand..thank u,, :)
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