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where is the table?

it is in the question

2x^2-8=0
2x^2=8
x^2=4
x=-2 or 2

got it?

is that forthe equation a.

yes

what about b and c

Did u understand it?

yes for thef irst one I did

2x^2-8<0
2x^2<8
x^2<4
x^2<(+-2)^2
Now, IF x^2<(+-a)^2 then -a

SO, can u complete it?

no do not get that one

2x^2-8<0
2x^2<8
x^2<4
x^2<(+-2)^2
IS it OKAY up to here?

yes

would it be 4

IF x^2<(+-a)^2 then -a

try to use it

I do notg et it

x^2<(+-2)^2
-2

got it?

yes but how do i figure it out

HINT: IF x^2<(+-a)^2
then -a

It is like formula

howdo i figurethef o rmula out

U want me to derive it?

what does that mean

hello what doyou m ean

I am sorry but I guess u need to revise your algebra once

soyoucannoth elp meany further

Sorry not so good at explaining things

ok Iwil l try someelse

@mathslover can help u?

He is good at explaining

I am well at explanation :)

socanyouhelpme mathsolver

I will be right back ... wait for 2 minutes please

so for equation b is it squareroot x2>squareroot 4.