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cdelomas Group Title

a table for y=2x^2-8 is given solve each equation. a. 2x^2-8=0,b. 2x^2-8<0,c. 2x^2-8>0.

  • one year ago
  • one year ago

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  1. sauravshakya Group Title
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    where is the table?

    • one year ago
  2. cdelomas Group Title
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    it is in the question

    • one year ago
  3. sauravshakya Group Title
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    2x^2-8=0 2x^2=8 x^2=4 x=-2 or 2

    • one year ago
  4. sauravshakya Group Title
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    got it?

    • one year ago
  5. cdelomas Group Title
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    is that forthe equation a.

    • one year ago
  6. sauravshakya Group Title
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    yes

    • one year ago
  7. cdelomas Group Title
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    what about b and c

    • one year ago
  8. sauravshakya Group Title
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    Did u understand it?

    • one year ago
  9. cdelomas Group Title
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    yes for thef irst one I did

    • one year ago
  10. sauravshakya Group Title
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    2x^2-8<0 2x^2<8 x^2<4 x^2<(+-2)^2 Now, IF x^2<(+-a)^2 then -a<x<a

    • one year ago
  11. sauravshakya Group Title
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    SO, can u complete it?

    • one year ago
  12. cdelomas Group Title
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    no do not get that one

    • one year ago
  13. sauravshakya Group Title
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    2x^2-8<0 2x^2<8 x^2<4 x^2<(+-2)^2 IS it OKAY up to here?

    • one year ago
  14. cdelomas Group Title
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    yes

    • one year ago
  15. cdelomas Group Title
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    would it be 4

    • one year ago
  16. sauravshakya Group Title
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    IF x^2<(+-a)^2 then -a<x<a

    • one year ago
  17. sauravshakya Group Title
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    try to use it

    • one year ago
  18. cdelomas Group Title
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    I do notg et it

    • one year ago
  19. sauravshakya Group Title
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    x^2<(+-2)^2 -2<x<2

    • one year ago
  20. sauravshakya Group Title
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    got it?

    • one year ago
  21. cdelomas Group Title
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    yes but how do i figure it out

    • one year ago
  22. sauravshakya Group Title
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    HINT: IF x^2<(+-a)^2 then -a<x<a

    • one year ago
  23. sauravshakya Group Title
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    It is like formula

    • one year ago
  24. cdelomas Group Title
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    howdo i figurethef o rmula out

    • one year ago
  25. sauravshakya Group Title
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    U want me to derive it?

    • one year ago
  26. cdelomas Group Title
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    what does that mean

    • one year ago
  27. cdelomas Group Title
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    hello what doyou m ean

    • one year ago
  28. sauravshakya Group Title
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    I am sorry but I guess u need to revise your algebra once

    • one year ago
  29. cdelomas Group Title
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    soyoucannoth elp meany further

    • one year ago
  30. sauravshakya Group Title
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    Sorry not so good at explaining things

    • one year ago
  31. cdelomas Group Title
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    ok Iwil l try someelse

    • one year ago
  32. sauravshakya Group Title
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    @mathslover can help u?

    • one year ago
  33. sauravshakya Group Title
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    He is good at explaining

    • one year ago
  34. mathslover Group Title
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    I am well at explanation :)

    • one year ago
  35. cdelomas Group Title
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    socanyouhelpme mathsolver

    • one year ago
  36. mathslover Group Title
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    I will be right back ... wait for 2 minutes please

    • one year ago
  37. wio Group Title
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    \[ 2x^2-8<0 \\ 2x^2<8 \\ x^2<4 \\ \sqrt{x^2}<\sqrt{4} \]Now it is important to remember that \(\sqrt{\quad}\) mean the "positive square root" (not the negative one) and that \(\sqrt{a^2}\) is the definition of of the absolute value.\[ |x| < 2 \]

    • one year ago
  38. wio Group Title
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    To solve absolute value equations, we have to split it up into two cases. Case 1: Assume \(x\) (the thing in the absolute value) is positive. \[ |x| < 2 \\ x<2 \] That was easy. Case 2: Assume \(x\) is negative: \[ |x| < 2 \\ -x < 2 \\ x > -2 \]Remember that if \(x\) is negative, then \(|x| =-x\) because the absolute value bars had to flip the sign to make \(x\) positive. Also remember that when you multiply/divide both sides of an inequality by a negative number, the equality flips. Hence \(<\) became \(>\) in this instance.

    • one year ago
  39. wio Group Title
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    Notation allows us to conveniently combine the expressions \(x < 2\) and \(x > -2\) into \(-2 < x < 2\). Does this help, @cdelomas ?

    • one year ago
  40. wio Group Title
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    One thing worthy of committing to memory is that: \[ |x| < a \implies -a < x < a \\ |x| > a \implies x < -a,\quad x > a \]

    • one year ago
  41. cdelomas Group Title
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    so for equation b is it squareroot x2>squareroot 4.

    • one year ago
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