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 2 years ago
a ball thrown straight up into the air so that its height in feet after t seconds is given by s(t)= 128t16t^2.. so, find the average velocity of the ball during tie interval (2,2.1)
 2 years ago
a ball thrown straight up into the air so that its height in feet after t seconds is given by s(t)= 128t16t^2.. so, find the average velocity of the ball during tie interval (2,2.1)

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sha0403
 2 years ago
Best ResponseYou've already chosen the best response.0yes.. after that i get 12832t.. so what should i do that given time interval (2, 2.1)

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2U need to find {s'(2) + s'(2.1)}/2

sha0403
 2 years ago
Best ResponseYou've already chosen the best response.0why it divide by 2? can u explain to me?

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2Because we are calculating avereage of two velocities

sha0403
 2 years ago
Best ResponseYou've already chosen the best response.0oh like that..if we want to calculate average between 3 velocity,, we should divide by 3 also?

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2add three valocities and dvide it by

sha0403
 2 years ago
Best ResponseYou've already chosen the best response.0ok.... i would like to ask u something.. if the question ask to find instantaneous velocity at t=2.. what the mean of instantaneous/

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2instantaneous means velocity of that body at that particular time

wio
 2 years ago
Best ResponseYou've already chosen the best response.1Umm, one thing I'd like to note is that @sauravshakya 's method for finding the average value works for lines. In this case velocity is indeed linear so it will work, though.

wio
 2 years ago
Best ResponseYou've already chosen the best response.1Wait, actually @sauravshakya , the units don't seem to work out with your method. You have \(\frac{m/s}{s}\), which is acceleration.

wio
 2 years ago
Best ResponseYou've already chosen the best response.1I think we don't need to do any calculus at all here. It's just: \[ \large \frac{s(t_f)s(t_i)}{t_ft_i} \]

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2I was just calculating average velocity

wio
 2 years ago
Best ResponseYou've already chosen the best response.1Wow, that's right. I was wrong.

sha0403
 2 years ago
Best ResponseYou've already chosen the best response.0@wio your formula when i should use it? what the kind of question?

wio
 2 years ago
Best ResponseYou've already chosen the best response.1Anyway, I'm thinking that the average velocity, given velocity is: \[ \large \overline{v(t)} = \frac{1}{t_ft_i}\int_{t_i}^{t_f} v(t) dt \]Note that \(s(t) = \int v(t) dt \), which gives us (by fundamental theorem of calc: \[ \frac{s(t_f)  s(t_i)}{t_f  t_i} \]

sha0403
 2 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya and @wio ..thank u very much
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