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a ball thrown straight up into the air so that its height in feet after t seconds is given by s(t)= 128t16t^2.. so, find the average velocity of the ball during tie interval (2,2.1)
 one year ago
 one year ago
a ball thrown straight up into the air so that its height in feet after t seconds is given by s(t)= 128t16t^2.. so, find the average velocity of the ball during tie interval (2,2.1)
 one year ago
 one year ago

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sha0403Best ResponseYou've already chosen the best response.0
yes.. after that i get 12832t.. so what should i do that given time interval (2, 2.1)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
U need to find {s'(2) + s'(2.1)}/2
 one year ago

sha0403Best ResponseYou've already chosen the best response.0
why it divide by 2? can u explain to me?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Because we are calculating avereage of two velocities
 one year ago

sha0403Best ResponseYou've already chosen the best response.0
oh like that..if we want to calculate average between 3 velocity,, we should divide by 3 also?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
add three valocities and dvide it by
 one year ago

sha0403Best ResponseYou've already chosen the best response.0
ok.... i would like to ask u something.. if the question ask to find instantaneous velocity at t=2.. what the mean of instantaneous/
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
instantaneous means velocity of that body at that particular time
 one year ago

wioBest ResponseYou've already chosen the best response.1
Umm, one thing I'd like to note is that @sauravshakya 's method for finding the average value works for lines. In this case velocity is indeed linear so it will work, though.
 one year ago

wioBest ResponseYou've already chosen the best response.1
Wait, actually @sauravshakya , the units don't seem to work out with your method. You have \(\frac{m/s}{s}\), which is acceleration.
 one year ago

wioBest ResponseYou've already chosen the best response.1
I think we don't need to do any calculus at all here. It's just: \[ \large \frac{s(t_f)s(t_i)}{t_ft_i} \]
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
I was just calculating average velocity
 one year ago

wioBest ResponseYou've already chosen the best response.1
Wow, that's right. I was wrong.
 one year ago

sha0403Best ResponseYou've already chosen the best response.0
@wio your formula when i should use it? what the kind of question?
 one year ago

wioBest ResponseYou've already chosen the best response.1
Anyway, I'm thinking that the average velocity, given velocity is: \[ \large \overline{v(t)} = \frac{1}{t_ft_i}\int_{t_i}^{t_f} v(t) dt \]Note that \(s(t) = \int v(t) dt \), which gives us (by fundamental theorem of calc: \[ \frac{s(t_f)  s(t_i)}{t_f  t_i} \]
 one year ago

sha0403Best ResponseYou've already chosen the best response.0
@sauravshakya and @wio ..thank u very much
 one year ago
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