A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
anonymous
 3 years ago
how to sum geometric series 5*(1,06)^3 + 5*(1,06)^4 +...+ 5*(1,06)^n1, so as to end up with 5*((1(1,06)^1n) / (1,06^2  1,06)). thanks
anonymous
 3 years ago
how to sum geometric series 5*(1,06)^3 + 5*(1,06)^4 +...+ 5*(1,06)^n1, so as to end up with 5*((1(1,06)^1n) / (1,06^2  1,06)). thanks

This Question is Closed

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.2Hint  It's an old method with some application. 1) \(r + r^{2} + r^{3} + ... + r^{n} = S\) Multiply by r 2) \(r^{2} + r^{3} + r^{4} + ... + r^{n+1} = Sr\) Subtract 2) from 1) \(r  r^{n+1} = S  Sr\) Can you solve for S?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0great thanks tkhunny, i will study this!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.