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how to sum geometric series 5*(1,06)^3 + 5*(1,06)^4 +...+ 5*(1,06)^n1, so as to end up with 5*((1(1,06)^1n) / (1,06^2  1,06)). thanks
 one year ago
 one year ago
how to sum geometric series 5*(1,06)^3 + 5*(1,06)^4 +...+ 5*(1,06)^n1, so as to end up with 5*((1(1,06)^1n) / (1,06^2  1,06)). thanks
 one year ago
 one year ago

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tkhunnyBest ResponseYou've already chosen the best response.2
Hint  It's an old method with some application. 1) \(r + r^{2} + r^{3} + ... + r^{n} = S\) Multiply by r 2) \(r^{2} + r^{3} + r^{4} + ... + r^{n+1} = Sr\) Subtract 2) from 1) \(r  r^{n+1} = S  Sr\) Can you solve for S?
 one year ago

business1Best ResponseYou've already chosen the best response.0
great thanks tkhunny, i will study this!
 one year ago
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