At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

\[\huge \lim_{x \rightarrow 5} \frac{ 1 }{ x-5 }\]

Does it exist?

yes

Are you sure about that?

not really

i completely forgot how to solve these except for direct substitution

okay thank you :)

how would i solve limits that have fractions over fraction though ?

Start by simplifying it into a single fraction.

\[\large \lim x \rightarrow -3 \frac{ \frac{ 1 }{ x } +\frac{ 1 }{ 3 }}{x+3}\]

ohh okay

(a/b)/c = a/(bc) and a/(b/c) = (ac)/b

Okay you need to add up the \(1/x\) and \(1/3\).

a/b + c/d = (ad + bc)/(bd)

\[\large \lim \rightarrow -3 \frac{ 3+x }{ 3x^2+9x }\]

This function becomes continuous once you have manipulated it a bit.

Continuous at \(-3\) at least.

what does that mean ?

ohh thankyou !