A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge \lim_{x \rightarrow 5} \frac{ 1 }{ x5 }\]

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0i completely forgot how to solve these except for direct substitution

wio
 one year ago
Best ResponseYou've already chosen the best response.3Well, when you can't directly substitute, I recommend putting in really close values (e.g. 5.001 and 4.999).

wio
 one year ago
Best ResponseYou've already chosen the best response.3Make sure it exists first. Then you can use things like squeeze theorem / l'Hospital's rule. There is no sure way of doing limits, only a series of methods.

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0how would i solve limits that have fractions over fraction though ?

wio
 one year ago
Best ResponseYou've already chosen the best response.3Start by simplifying it into a single fraction.

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \lim x \rightarrow 3 \frac{ \frac{ 1 }{ x } +\frac{ 1 }{ 3 }}{x+3}\]

wio
 one year ago
Best ResponseYou've already chosen the best response.3(a/b)/c = a/(bc) and a/(b/c) = (ac)/b

wio
 one year ago
Best ResponseYou've already chosen the best response.3Okay you need to add up the \(1/x\) and \(1/3\).

wio
 one year ago
Best ResponseYou've already chosen the best response.3a/b + c/d = (ad + bc)/(bd)

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \lim \rightarrow 3 \frac{ 3+x }{ 3x^2+9x }\]

wio
 one year ago
Best ResponseYou've already chosen the best response.3I don't think you're doing it correctly. \[ \frac{1}{x} +\frac{1}{3} = \frac{x+3}{3x} \]And then \[\Large \frac{\frac{x+3}{3x}}{x+3} = \frac{x+3}{3x(x+3)} = \frac{1}{3x} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.3This function becomes continuous once you have manipulated it a bit.

wio
 one year ago
Best ResponseYou've already chosen the best response.3Continuous at \(3\) at least.

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0what does that mean ?

wio
 one year ago
Best ResponseYou've already chosen the best response.3What does continuous mean? It means: 1) \(f(a)\) is defined 2) \(\lim_{x \to a}f(x)\) exists and 3) \(\lim_{x \to a}f(x) = f(a) \) In general, it means you can just plug \(a\) into \(f(x)\) and get the answer to the limit.

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0Ask yourself, what is a limit? Really. It's what happens as you approach a number from both sides. So to approach a number, you can plug in numbers close to it, like 4.999 is close to 5 on the left side while 5.00001 is close on the right side. Make sense? Plugging these in and seeing what you approach is really the essence of a limit and understanding that will let you solve any limit problem by simply graphing it when you get stumped.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.