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sp0iltbrat

  • 2 years ago

question in attachment.

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  1. sp0iltbrat
    • 2 years ago
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  2. sp0iltbrat
    • 2 years ago
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    need help with part (b) part (a) was written because part is follow on from part (a).

  3. sp0iltbrat
    • 2 years ago
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    * part (a)

  4. sp0iltbrat
    • 2 years ago
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    i ve done part (a)

  5. Mimi_x3
    • 2 years ago
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    \[\int \frac{1+ln(u)}{u^2}du =>\int\frac{1}{u^{2}} +\frac{ln(u)}{u^{2}} => \int u^{-2} du + \int ln(u)*u^{-2} dx \] Maybe..integration by parts.

  6. hartnn
    • 2 years ago
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    its written hence evaluate, so integrate, e^(-x)(2+x)dx by parts.

  7. Mimi_x3
    • 2 years ago
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    lol, yeah..i skipped that part..but its still doable from what i wrote..

  8. sp0iltbrat
    • 2 years ago
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    thnx guys i've been trying to figure out this Q by simple integration for the previous hr

  9. hartnn
    • 2 years ago
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    by parts is required...

  10. sp0iltbrat
    • 2 years ago
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    Anyway hw did u lyk my skills of writing this Q in paint ?? :P

  11. hartnn
    • 2 years ago
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    very impressive.

  12. hba
    • 2 years ago
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    Next time please use the equation tool we have here. It is easy to see :)

  13. sp0iltbrat
    • 2 years ago
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    ahaha thnx hartnn :))

  14. hartnn
    • 2 years ago
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    welcome ^_^

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spraguer (Moderator)
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