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mathhelp7
Group Title
What is the solution to the equation? SQRT 2x + 10 – 6 =2
 one year ago
 one year ago
mathhelp7 Group Title
What is the solution to the equation? SQRT 2x + 10 – 6 =2
 one year ago
 one year ago

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tkhunny Group TitleBest ResponseYou've already chosen the best response.0
This? \(\sqrt{2x+10}  6 = 2\)
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
yes. would u pls show work? thx!
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
You need a plan. You must end with "x = simething", right?
 one year ago

tyteen4a03 Group TitleBest ResponseYou've already chosen the best response.0
@mathhelp7 For these type of functions, you will need to make it as a quadratic equation. Squaring every term in the equation should do the trick.
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
thanks! i still need help.
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
Add 6 both sides and plz tell me vat u get @mathhelp7
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
2x + 19 = 2 + 6
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
Right hand side part is ok. but plz check the left hand side part
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
oh, 2x + 16 = 2 + 6
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
remember 2x+10 is within sqrt and not 6. U cannot add 6 to \(\sqrt{2x+10}\) and make it \(sqrt{2x+16}\) getting it?
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\(\sqrt{2x+10}6=2\) \(\sqrt{2x+10}6+6=2+6\) \(\sqrt{2x+10}=2+6\) Gettin this @mathhelp7?
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
Yes. so do i cancel 6 out which will make it  8 = 8?
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
Sorry i dnt get u
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
i wasn't sure if i needed to continue from where you stopped.
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
ya u need to:) 2+6=8 so \(\sqrt{2x+10}=8\) Square both sides and plz tell me vat u get. \((\sqrt a)^2=a\)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\((\sqrt{2x+10})^2=?\) \((8)^2=?\)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\((8)^2=64\) is right.:) What abt \((\sqrt{2x+10})^2=?\)
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
sqrt2x+10 = (x + 5) (x – 5) = 64? i'm lost :(
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
noo. dw:1356933328085:dw can u find nw?
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
Thanks for your help and patience. i give up!
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
That's k:) Let me tell it again then. \((\sqrt{2x+10})^2=2x+10\) Is it clear?
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
ok. i get it but what happens to the 64?
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
Ya nw equate them. i.e 2x+10=64 Nw solve fro x. Can u do it?
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
i think so. is it x=56?
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
i think so. is it x=52?
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
noo. Plz follw the steps. 1.Subtract 10 both sides 2.Divide by 2 both sides
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
ya. perfect:)
 one year ago

mathhelp7 Group TitleBest ResponseYou've already chosen the best response.0
oh. thank u, thank u!!!
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
welcome:)
 one year ago
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