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anonymous
 3 years ago
An object spring system moving with simple harmonic motion has an amplitude A.
a) What is the total energy of the system in terms of k and A only? (E=1/2kA^2)
b) Suppose at a certain instant the kinetic energy is twice the elastic potential energy. Write an equation describing this situation, using only the variables for the mass m, velocity v, spring constant k, and position x. (1/2mv^2=kx^2)
c) Using the results of parts (a) and (b) and the conservation of energy equation, find the positions x of the object when its kinetic energy equals twice the potential energy stored in the spring.
anonymous
 3 years ago
An object spring system moving with simple harmonic motion has an amplitude A. a) What is the total energy of the system in terms of k and A only? (E=1/2kA^2) b) Suppose at a certain instant the kinetic energy is twice the elastic potential energy. Write an equation describing this situation, using only the variables for the mass m, velocity v, spring constant k, and position x. (1/2mv^2=kx^2) c) Using the results of parts (a) and (b) and the conservation of energy equation, find the positions x of the object when its kinetic energy equals twice the potential energy stored in the spring.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the total energy is kA^2/2=P.E+k.E=3P.E This gives P.E=kA^2/6=kx^2/2 Solve it for x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I need part C. I'm not sure how to exactly get it but the answer is: x=A/3^1/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you can expand your steps a bit, I would appreciate it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the total energy is conserved in SHM and is equal to kA^2/2 at all the times. The total energy is the sum of the potential energy and the kinetic energy. Hence kA^2/2=P.E+K.E Given K.E.=2P.E. at some instant and we have to find the value of x at which thia will happen So kA62/2=P.E+2P.E=3P.E P.E=kA^2/6 But P.E=kx^2/2 So kx^2/2=kA^2/6 This can be solved for x and x is indeed equal to A/3^1/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh all right. Thanks! :)
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