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 one year ago
coefficient of friction between the 2 blocks is U and the surface below the bigger block is smooth .
Find the min and max force that can be applied in order to keep the smaller blocks at rest with respect to the bigger block.
 one year ago
coefficient of friction between the 2 blocks is U and the surface below the bigger block is smooth . Find the min and max force that can be applied in order to keep the smaller blocks at rest with respect to the bigger block.

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shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1dw:1356948181967:dw

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1dw:1356949501640:dw is that right ?

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0sorry.. this is right! missed the pseudo on second small block..

VincentLyon.Fr
 one year ago
Best ResponseYou've already chosen the best response.0This problem was already solved on OS. Will try to find the reference.

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1eqns of motion would be Umg + m(F/M) = T and T + Um(F/M) = mg => Umg + m(F/M) + Um(F/M) = mg the value of F that am getting is not right ! ;)

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.1dw:1356961990631:dw

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.1Sorry that case was when it tends to move to the right

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.1Now, dw:1356962249332:dw

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.1Fr1= umg Fr2 =umF/(M+2m)

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.1F' = mF/(M+2m) W=mg

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.1From WFr2F'Fr1=0 we get F=g(M+2m)(1+u)(1u) From F'mgFr2Fr1=0 we get F =g(M+2m)(1+u)/(1u)

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1i see!! thanks a lot! that helped !

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1i understand it now..
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