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shubhamsrg

  • 3 years ago

coefficient of friction between the 2 blocks is U and the surface below the bigger block is smooth . Find the min and max force that can be applied in order to keep the smaller blocks at rest with respect to the bigger block.

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  1. shubhamsrg
    • 3 years ago
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    |dw:1356948181967:dw|

  2. shubhamsrg
    • 3 years ago
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    |dw:1356949501640:dw| is that right ?

  3. yrelhan4
    • 3 years ago
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    sorry.. this is right! missed the pseudo on second small block..

  4. Vincent-Lyon.Fr
    • 3 years ago
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    This problem was already solved on OS. Will try to find the reference.

  5. shubhamsrg
    • 3 years ago
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    eqns of motion would be Umg + m(F/M) = T and T + Um(F/M) = mg => Umg + m(F/M) + Um(F/M) = mg the value of F that am getting is not right ! ;)

  6. sauravshakya
    • 3 years ago
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    |dw:1356961990631:dw|

  7. sauravshakya
    • 3 years ago
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    Sorry that case was when it tends to move to the right

  8. sauravshakya
    • 3 years ago
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    Now, |dw:1356962249332:dw|

  9. sauravshakya
    • 3 years ago
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    Fr1= umg Fr2 =umF/(M+2m)

  10. sauravshakya
    • 3 years ago
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    F' = mF/(M+2m) W=mg

  11. sauravshakya
    • 3 years ago
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    From W-Fr2-F'-Fr1=0 we get F=g(M+2m)(1+u)(1-u) From F'-mg-Fr2-Fr1=0 we get F =g(M+2m)(1+u)/(1-u)

  12. shubhamsrg
    • 3 years ago
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    i see!! thanks a lot! that helped !

  13. shubhamsrg
    • 3 years ago
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    i understand it now..

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