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coefficient of friction between the 2 blocks is U and the surface below the bigger block is smooth .
Find the min and max force that can be applied in order to keep the smaller blocks at rest with respect to the bigger block.
 one year ago
 one year ago
coefficient of friction between the 2 blocks is U and the surface below the bigger block is smooth . Find the min and max force that can be applied in order to keep the smaller blocks at rest with respect to the bigger block.
 one year ago
 one year ago

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shubhamsrgBest ResponseYou've already chosen the best response.1
dw:1356948181967:dw
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
dw:1356949501640:dw is that right ?
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.0
sorry.. this is right! missed the pseudo on second small block..
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
This problem was already solved on OS. Will try to find the reference.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
eqns of motion would be Umg + m(F/M) = T and T + Um(F/M) = mg => Umg + m(F/M) + Um(F/M) = mg the value of F that am getting is not right ! ;)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
dw:1356961990631:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
Sorry that case was when it tends to move to the right
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
Now, dw:1356962249332:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
Fr1= umg Fr2 =umF/(M+2m)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
F' = mF/(M+2m) W=mg
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
From WFr2F'Fr1=0 we get F=g(M+2m)(1+u)(1u) From F'mgFr2Fr1=0 we get F =g(M+2m)(1+u)/(1u)
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
i see!! thanks a lot! that helped !
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
i understand it now..
 one year ago
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