shubhamsrg
  • shubhamsrg
coefficient of friction between the 2 blocks is U and the surface below the bigger block is smooth . Find the min and max force that can be applied in order to keep the smaller blocks at rest with respect to the bigger block.
Physics
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SOLVED
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katieb
  • katieb
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shubhamsrg
  • shubhamsrg
|dw:1356948181967:dw|
shubhamsrg
  • shubhamsrg
|dw:1356949501640:dw| is that right ?
yrelhan4
  • yrelhan4
sorry.. this is right! missed the pseudo on second small block..

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Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
This problem was already solved on OS. Will try to find the reference.
shubhamsrg
  • shubhamsrg
eqns of motion would be Umg + m(F/M) = T and T + Um(F/M) = mg => Umg + m(F/M) + Um(F/M) = mg the value of F that am getting is not right ! ;)
anonymous
  • anonymous
|dw:1356961990631:dw|
anonymous
  • anonymous
Sorry that case was when it tends to move to the right
anonymous
  • anonymous
Now, |dw:1356962249332:dw|
anonymous
  • anonymous
Fr1= umg Fr2 =umF/(M+2m)
anonymous
  • anonymous
F' = mF/(M+2m) W=mg
anonymous
  • anonymous
From W-Fr2-F'-Fr1=0 we get F=g(M+2m)(1+u)(1-u) From F'-mg-Fr2-Fr1=0 we get F =g(M+2m)(1+u)/(1-u)
shubhamsrg
  • shubhamsrg
i see!! thanks a lot! that helped !
shubhamsrg
  • shubhamsrg
i understand it now..

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