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shubhamsrg

coefficient of friction between the 2 blocks is U and the surface below the bigger block is smooth . Find the min and max force that can be applied in order to keep the smaller blocks at rest with respect to the bigger block.

  • one year ago
  • one year ago

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  1. shubhamsrg
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    |dw:1356948181967:dw|

    • one year ago
  2. shubhamsrg
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    |dw:1356949501640:dw| is that right ?

    • one year ago
  3. yrelhan4
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    sorry.. this is right! missed the pseudo on second small block..

    • one year ago
  4. Vincent-Lyon.Fr
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    This problem was already solved on OS. Will try to find the reference.

    • one year ago
  5. shubhamsrg
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    eqns of motion would be Umg + m(F/M) = T and T + Um(F/M) = mg => Umg + m(F/M) + Um(F/M) = mg the value of F that am getting is not right ! ;)

    • one year ago
  6. sauravshakya
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    |dw:1356961990631:dw|

    • one year ago
  7. sauravshakya
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    Sorry that case was when it tends to move to the right

    • one year ago
  8. sauravshakya
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    Now, |dw:1356962249332:dw|

    • one year ago
  9. sauravshakya
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    Fr1= umg Fr2 =umF/(M+2m)

    • one year ago
  10. sauravshakya
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    F' = mF/(M+2m) W=mg

    • one year ago
  11. sauravshakya
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    From W-Fr2-F'-Fr1=0 we get F=g(M+2m)(1+u)(1-u) From F'-mg-Fr2-Fr1=0 we get F =g(M+2m)(1+u)/(1-u)

    • one year ago
  12. shubhamsrg
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    i see!! thanks a lot! that helped !

    • one year ago
  13. shubhamsrg
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    i understand it now..

    • one year ago
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