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Let ABC be a triangle such that <ACB = 30 let a,b,c denote the lenght of the sides oppositr to A,B,C. The Values for which a=x^2 + x + 1 , b = x^2 1 and c= 2x +1 is?
 one year ago
 one year ago
Yahoo! Group Title
Let ABC be a triangle such that <ACB = 30 let a,b,c denote the lenght of the sides oppositr to A,B,C. The Values for which a=x^2 + x + 1 , b = x^2 1 and c= 2x +1 is?
 one year ago
 one year ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
a right triangle, or just some triangle?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
law of cosines is my best bet
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
no that was a lousy bet law of sines is easier
 one year ago

OpenStudier Group TitleBest ResponseYou've already chosen the best response.0
Law of sines: \[\frac{ \sin A }{ a }=\frac{ \sin B }{ b }\]
 one year ago

OpenStudier Group TitleBest ResponseYou've already chosen the best response.0
Do you understand?
 one year ago

OpenStudier Group TitleBest ResponseYou've already chosen the best response.0
Actually, we can compare all three: \[\frac{ \sin 30 }{ 2x+1 }=\frac{ \sin A }{ x^2+x+1 }=\frac{ \sin B }{ x^21 }\]
 one year ago

OpenStudier Group TitleBest ResponseYou've already chosen the best response.0
To solve for angles A and B, we know they are equal to 120 degrees (18030).
 one year ago

neba.zi Group TitleBest ResponseYou've already chosen the best response.0
from above we can calculate the intersection of the sides it help us to find the value of x i.e let \[^{x2+x+1= ^{x21}}\] because the y intersect at C i think we can solve like these
 one year ago

melanka Group TitleBest ResponseYou've already chosen the best response.0
use cosine rule, cos30=(3^1/2)/2=((x^2+x+1)^2+(x^21)^2(2x+1)^2)/2(x^2+x+1)(x^21) 3^1/2=(2x^4+2x^33x^22x+1)/(x^2+x+1)(x^21) by factorising the numerator 2x^4+2x^33x^22x+1=(2x^2+2x1)(x^21) then solve 3^1/2(x^2+x+1)=2x^2+2x1, its just a quadratic equation. sine rule would be too complex in this case.
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\[(2x+1)^2=(x^2 + x + 1)^2+(x^21)^22(x^2+x+1)(x^21)\frac{\sqrt{3}}{2}\] but really i am wondering if this is a right triangle, because this looks extra annoying to solve
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
apparently 1 works, but that gives you nothing because then one side would be 0
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\(1+\sqrt{3}\) works as well, maybe that is a good answer
 one year ago
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