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 one year ago
Let ABC be a triangle such that <ACB = 30 let a,b,c denote the lenght of the sides oppositr to A,B,C. The Values for which a=x^2 + x + 1 , b = x^2 1 and c= 2x +1 is?
 one year ago
Let ABC be a triangle such that <ACB = 30 let a,b,c denote the lenght of the sides oppositr to A,B,C. The Values for which a=x^2 + x + 1 , b = x^2 1 and c= 2x +1 is?

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satellite73
 one year ago
Best ResponseYou've already chosen the best response.0a right triangle, or just some triangle?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0law of cosines is my best bet

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0no that was a lousy bet law of sines is easier

OpenStudier
 one year ago
Best ResponseYou've already chosen the best response.0Law of sines: \[\frac{ \sin A }{ a }=\frac{ \sin B }{ b }\]

OpenStudier
 one year ago
Best ResponseYou've already chosen the best response.0Do you understand?

OpenStudier
 one year ago
Best ResponseYou've already chosen the best response.0Actually, we can compare all three: \[\frac{ \sin 30 }{ 2x+1 }=\frac{ \sin A }{ x^2+x+1 }=\frac{ \sin B }{ x^21 }\]

OpenStudier
 one year ago
Best ResponseYou've already chosen the best response.0To solve for angles A and B, we know they are equal to 120 degrees (18030).

neba.zi
 one year ago
Best ResponseYou've already chosen the best response.0from above we can calculate the intersection of the sides it help us to find the value of x i.e let \[^{x2+x+1= ^{x21}}\] because the y intersect at C i think we can solve like these

melanka
 one year ago
Best ResponseYou've already chosen the best response.0use cosine rule, cos30=(3^1/2)/2=((x^2+x+1)^2+(x^21)^2(2x+1)^2)/2(x^2+x+1)(x^21) 3^1/2=(2x^4+2x^33x^22x+1)/(x^2+x+1)(x^21) by factorising the numerator 2x^4+2x^33x^22x+1=(2x^2+2x1)(x^21) then solve 3^1/2(x^2+x+1)=2x^2+2x1, its just a quadratic equation. sine rule would be too complex in this case.

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0\[(2x+1)^2=(x^2 + x + 1)^2+(x^21)^22(x^2+x+1)(x^21)\frac{\sqrt{3}}{2}\] but really i am wondering if this is a right triangle, because this looks extra annoying to solve

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0apparently 1 works, but that gives you nothing because then one side would be 0

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0\(1+\sqrt{3}\) works as well, maybe that is a good answer
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