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julliemyers
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In the equation y = ab(x – h) + k, how does the value of k affect the graph?
 one year ago
 one year ago
julliemyers Group Title
In the equation y = ab(x – h) + k, how does the value of k affect the graph?
 one year ago
 one year ago

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Hero Group TitleBest ResponseYou've already chosen the best response.4
@julliemyers, do you have an idea of what the answer might be?
 one year ago

julliemyers Group TitleBest ResponseYou've already chosen the best response.1
yes im thinkn that the value of K will raise the entire graph of the function by k units.
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.4
raise it how? More detail please.
 one year ago

julliemyers Group TitleBest ResponseYou've already chosen the best response.1
Im not sure, i know that the value of K will either have an increase in the graph or a decrease, so im going with increase @Falkqwer
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.4
Yes, that is correct. The graph will increase depending on the value of k, assuming that k is positive.
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.4
Although, it's more accurate to indicate direction of the graph (up, down, left, right).
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
it shifts the graph k unit upward
 one year ago

julliemyers Group TitleBest ResponseYou've already chosen the best response.1
^So increse.? @Hero it doesnt give nor ask for the value of K but im assumong by the equation they give y = ab(x – h) + k that k is positve.
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.4
Well, yes, it is necessary to mention the possibilities when it comes to variables in a graph because the direction on the graph will depend on the value of k. If k is positive, the graph shifts upward, if the value of k is negative, it shifts downward. So you always have to account for that.
 one year ago

julliemyers Group TitleBest ResponseYou've already chosen the best response.1
Ok(: Thankks!
 one year ago
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