Koda
Write the equation of a line that is parallel to the line 2x+y=8 and passes through the point (-2,1)
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Parallel lines have the same slope. So first, find out the slope of 2x + y = 8, by putting it in y = mx + b
Koda
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y=2x+8
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So the slope is 2
Now we're given the points (-2, 1)
So slope = 2
Points = (-2, 1)
Plug those into: y - y1 = m(x - x1) Where y1 and x1 are points and m is the slope
Koda
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So the equation is y-1=2x+4
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No put that in y = mx + b
Koda
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y=2x+4
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There's your equation.
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Thanks
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