anonymous
  • anonymous
/Users/doreltibi/Desktop/Screen Shot 2012-12-31 at 11.02.38 AM.png
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
...
anonymous
  • anonymous
anonymous
  • anonymous
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geerky42
  • geerky42
|dw:1356980675825:dw|
geerky42
  • geerky42
Or you can divide kite into four triangles then find the area of each of them then add them together.
anonymous
  • anonymous
so for my problem it would be the following: 1/2 (15+7) (4+x) 1/2 (88+22x) 1/2 (110x) Area= 55x
anonymous
  • anonymous
?
geerky42
  • geerky42
You got it wrong, x = 7, y = 15, z = 4
anonymous
  • anonymous
so the area would be 13
geerky42
  • geerky42
133* Yeah.
anonymous
  • anonymous
1/2 (7+7) (15+4) 1/2(14) (19) Area=1/2(266) Area = 133

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