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kirk.freedman

  • 2 years ago

What is the solution of the equation?

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  1. kirk.freedman
    • 2 years ago
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  2. kirk.freedman
    • 2 years ago
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    I would like help on how to do this problem please.

  3. hartnn
    • 2 years ago
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    first isolate \(\sqrt[5]{(x+3)^3}\) can u ?

  4. kirk.freedman
    • 2 years ago
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    No, I'm not sure how you would do that

  5. hartnn
    • 2 years ago
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    subtract 3 on both sides, what u get ?

  6. kirk.freedman
    • 2 years ago
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    oh i see, you get the same on the right minus the 3 and it = 24

  7. kirk.freedman
    • 2 years ago
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    left side*

  8. kirk.freedman
    • 2 years ago
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    |dw:1356996161879:dw|

  9. hartnn
    • 2 years ago
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    yes, now divide by 3 on both sides, what u get ?

  10. kirk.freedman
    • 2 years ago
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    |dw:1356996206975:dw|

  11. hartnn
    • 2 years ago
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    right, now raise 5th power on both sides, can u ?

  12. kirk.freedman
    • 2 years ago
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    |dw:1356996275148:dw|

  13. xkylex
    • 2 years ago
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    thx

  14. hartnn
    • 2 years ago
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    i think you should keep that as 8^5 only.

  15. kirk.freedman
    • 2 years ago
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    oh ok, now i distribute the ^2 on the left?

  16. kirk.freedman
    • 2 years ago
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    *^3

  17. hartnn
    • 2 years ago
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    now, write 8=2^3 and take cube root on both sides.

  18. hartnn
    • 2 years ago
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    need help with this? i think you try once...

  19. kirk.freedman
    • 2 years ago
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    I'm sorry, you lost me there

  20. kirk.freedman
    • 2 years ago
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    No, I just have no idea, can you draw this step for me please?

  21. hartnn
    • 2 years ago
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    |dw:1356996503357:dw| |dw:1356996534417:dw| got this ?

  22. kirk.freedman
    • 2 years ago
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    Ohhh, yeah I get it now

  23. hartnn
    • 2 years ago
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    |dw:1356996601632:dw|

  24. hartnn
    • 2 years ago
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    ok, can u find x now ??

  25. kirk.freedman
    • 2 years ago
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    30?

  26. hartnn
    • 2 years ago
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    x+2 =2^5=32 x=32-2=30 yes! correct :)

  27. hartnn
    • 2 years ago
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    @xkylex did u get all of this? any doubts ?

  28. kirk.freedman
    • 2 years ago
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    Hey, thanks so much, your help is very greatly appreciated:)

  29. xkylex
    • 2 years ago
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    Yes! It was an excellent explanation!

  30. hartnn
    • 2 years ago
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    welcome to both ^_^

  31. xkylex
    • 2 years ago
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    kirk.freedman, I guess we are doing the same test, lol. Best of luck to you.

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