Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

jennychan12

  • 3 years ago

Explain this? A skier traveling 12.0 m/s reaches the foot of a steady upward 18° incline and glides 12.2 m up along this slope before coming to rest. What is the average coefficient of friction?

  • This Question is Closed
  1. jennychan12
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i know that |dw:1356999791579:dw|

  2. jennychan12
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i know it's non conservative, but what about the mass? because the W(fr) has no mass attached to it.

  3. Diwakar
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Find the average retardation by v^2-u^2=2as where final velocity v=0 initial velocity u=12m/s distance travelled=12.2m After that use a=gsin(18)+xgcos(18) to solve for x, the coefficent of friction

  4. jennychan12
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so the masses basically just cancel out? thanks.

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy